acceleration= change in velocity/ time taken
initial velocity=(36×1000m)/3600
= 10m/s
final velocity= (54×1000m)/3600
=15m/s
change in velocity= final - initial
=15 - 10
=5m/s
time taken = 5s
acceleration=15/5
=3metre per second square
Answer:
Maximum speed ( v ) = 10.4 m/s (Approx)
Explanation:
Given:
Amplitude A = 15.0 cm = 0.15 m
Frequency f = 11.0 cycles/s (Hz)
Find:
Maximum speed ( v )
Computation:
Angular frequency = 2πf
Angular frequency = 2π(11)
Angular frequency = 69.14
Maximum speed ( v ) = WA
Maximum speed ( v ) = 69.14 x 0.15
Maximum speed ( v ) = 10.371
Maximum speed ( v ) = 10.4 m/s (Approx)
Answer:
a) initial position = 10m
b) average velocity = 30m/s
Explanation:
The general equation of a motion with constant velocity is given by:
(1)
So: initial position
v: average velocity
t: time
You have the following equation:
(2)
If you compare the equations (1) and (2) you obtain that:
hence:
a) initial position = 10m
b) average velocity = 30m/s
Answer:
50m; 0m/s.
Explanation:
Given the following data;
Initial velocity = 20m/s
Acceleration, a = - 4m/s²
Time, t = 5secs
To find the displacement, we would use the second equation of motion;
Substituting into the equation, we have;
S = 50m
Next, to find the final velocity, we would use the third equation of motion;
Where;
- V represents the final velocity measured in meter per seconds.
- U represents the initial velocity measured in meter per seconds.
- a represents acceleration measured in meters per seconds square.
<em>Substituting into the equation, we have;</em>
V = 0m/s
<em>Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.</em>