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4 years ago

7

Along the frictionless path you have chosen, the main force(s) acting on the puck after receiving the kick is (are):

1 answer:

Vaselesa [24]4 years ago

5 0

Gravity, and Normal. Check the comments for why Applied isn't one.

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What will a spring scale read for the weight of a 57.0-kg woman in an elevator that moves upward with constant speed of 5.0 m/s

Tanzania [10]

The spring scale will read 559 Newton's or 125.7 pounds.

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3 years ago

Indicate whether the statement is true or false. an astronaut weighs the same on earth as in space.

tino4ka555 [31]

Weight is different (but mass is the same)

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3 years ago

Read 2 more answers

A football punker attempts to kick the football so that it lands on the ground 67.0 m from where it is kicked and stays in the a

Flauer [41]

To solve this problem we will apply the linear motion kinematic equations. We will find the two components of velocity and finally by geometric and vector relations we will find both the angle and the magnitude of the vector. In the case of horizontal speed we have to

$v_x = \frac{x}{t}$

$v_x = \frac{67}{4.5}$

$v_x = 14.89m/s$

The vertical component of velocity is

$-h = v_y t -\frac{1}{2} gt^2$

Here,

h = Height

g = Gravitational acceleration

t = Time

$v_y$ = Vertical component of velocity

$-1.23 = v_y(4.5)-\frac{1}{2} (9.8)(4.5)^2$

$-1.23= 4.5v_y - 99.225$

$v_y = 21.77m/s$

The direction of the velocity will be given by the tangent of the components, then

$tan\theta = \frac{v_y}{v_x}$

$\theta = tan^{-1} (\frac{21.77}{14.89})$

$\theta = 55.59\°$

The magnitude is given vectorially as,

$|V| = \sqrt{v_x^2+v_y^2}$

$|V| = \sqrt{14.89^2 +21.77^2}$

$|V| = 26.37m/s$

Therefore the angle is 55.59° and the velocity is 26.37m/s

6 0

3 years ago

Can someone help me with the question i have already answered

antiseptic1488 [7]

Correctoooo loosisks

5 0

3 years ago

belka [17]

Answer:

2156 J

Explanation:

From the question,

Work done = Combined mass of the bucket and water×height×gravity.

W = (M+m)hg............................. Equation 1

Where M = mass of water, m = mass of the bucket, h = height, g = acceleration due to gravity.

Given: M = 20 kg, m = 2 kg, h = 10 m

Constant: g = 9.8 m/s²

Substitute these value into equation 1

W = (20+2)×10×9.8

W = 22×98

W = 2156 J

4 0

3 years ago