Answer:
- 168.25 ft
- 3.125 s
Step-by-step explanation:
It is almost too easy to let a graphing calculator show you the solution. (See attached)
_____
You may be expected to use some actual algebra (or even calculus) to find the solution.
If you've spent any time with quadratics, you know the vertex of ax²+bx+c is located at x=-b/(2a). Here, that means the time to get to the highest point is ...
... t = -100/(2·(-16)) = 100/32 = 3.125 . . . . seconds
Then the highest point is ...
... h(3.125) = -16·3.125² +100·3.125 +12 = 168.25 . . . . feet
_____
Or, you can put the equation into vertex form.
... h(t) = -16t² +100t +12
... = -16(t² +6.25t) +12
... = -16(t² +6.25t +3.125²) +12 +16·3.125² . . . . . add the square of half the t coefficient inside parentheses; add the opposite of the same amount outside parentheses
... = -16(t +3.125)² +168.25 . . . . . simplify
This tells us the peak of the travel of the bullet is at 168.25 ft after 3.125 seconds.
X=original length of each side of the square.
perimeter: sum of all sides=4(length of the side)
The length of each side of the new square will be= (x-2)
we can suggest this equation:
4(x-2)=48
We solve this equation:
4(x-2)=48
4x-8=48
4x=48+8
4x=56
x=56/4
x=14
Answer: the original length of each side of the square would be 14 in.
34-23 times (5-2) - 60
33-23 times (3) - 60
33 - 69 - 60
33- 9
24
i hope this helps! feel free to mark brainliest
Answer:
I believe 9 weeks
Step-by-step explanation:
take 46.96 and subtract 10.25 and you have 36 70 left he needs. 4.25x9 would be a little over 36.70 which is how much left u need