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Karo-lina-s [1.5K]
4 years ago
5

Non-self-supporting ladders must be placed or positioned at an angle where the horizontal distance from the top support to the f

oot of the ladder is _______ the working length of the ladder.
Physics
1 answer:
Elenna [48]4 years ago
6 0

Answer:

Shorter than(?)

Explanation:

What is it that you're looking for here? Is it just some random fill in the blank question?

My guess is that the horizontal distance has to be shorter than that of the ladder length because if it wasn't then the ladder would be laying down or maybe standing straight up... and you can't really use it normally like that... I'm sorry, where is the Physics in this question exactly?

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The pilot directs the aircraft to fly due north at 600km/h. A side-wind blows at
loris [4]

Answer:

678.2 km/h and 80.54° north of east

Explanation:

From the question,

Using pythagoras theorem,

a² = b²+c²..................... Equation 1

Where a = resultant velocity

Given: b = 600 km/h, c = 100 km/h

Substitute these values into equation 1

R² = 600²+100²

R² = 360000+10000

R² = 460000

R  = √460000

R = 678.2 km/h.

And the direction is

tanθ = 600/100

tanθ = 6

tanθ = 6

θ = tan⁻¹(6)

θ = 80.54°.

Hence the resultant velocity of the aircraft is 678.2 km/h and 80.54° north of east

3 0
3 years ago
Which planet, when viewed through a telescope, appears as a reddish ball interrupted by some permanent dark regions that change
Andrej [43]
The answer should be Mars. 
4 0
4 years ago
Read 2 more answers
A beam of light strikes a sheet of glass at an angle of 56.6° with the normal in air. You observe that red light makes an angle
Yuri [45]

Answer:

(a). Index of refraction are n_{red} = 1.344 & n_{violet} = 1.406

(b). The velocity of red light in the glass v_{red} = 2.23 ×10^{8} \ \frac{m}{s}

The velocity of violet light in the glass v_{violet} =2.13 ×10^{8} \ \frac{m}{s}

Explanation:

We know that

Law of reflection is

n_1 \sin\theta_{1} = n_2 \sin\theta_{2}

Here

\theta_1 = angle of incidence

\theta_2 = angle of refraction

(a). For red light

1 × \sin 56.6 = n_{red} × \sin 38.4

n_{red} = 1.344

For violet light

1 × \sin 56.6 = n_{violet} × \sin 36.4

n_{violet} = 1.406

(b). Index of refraction is given by

n = \frac{c}{v}

n_{red} = 1.344

v_{red} = \frac{c}{n_{red} }

v_{red} = \frac{3(10^{8} )}{1.344}

v_{red} = 2.23 ×10^{8} \ \frac{m}{s}

This is the velocity of red light in the glass.

The velocity of violet light in the glass is given by

v_{violet} = \frac{3(10^{8} )}{1.406}

v_{violet} =2.13 ×10^{8} \ \frac{m}{s}

This is the velocity of violet light in the glass.

8 0
3 years ago
If a car rolls gently off a vertical cliff, how long does it take to reach 90km/hr.
Naddik [55]
90 km/h : 3.6 = 25 m/s. If you know that on earth g = 9.81 m/s^2, then all you have to do is divide the speed by g. 25/9.81 = 2.548 seconds

At least, if by 'gently rolls off a vertical cliff' means that your starting velocity equals zero.
5 0
3 years ago
A bridge that was 5.0 m long has been washed out by the rain several days ago. How fast must a car be going to successfully jump
amid [387]

Answer:

Speed, v = 7.83 m/s

Explanation:

It is given that,

Length of the bridge, l = 5 m

The road on the far side is 2.0 m lower than the road on this side, x = 2 m

The horizontal distance covered by the car is 5 meters and the vertical distance covered by the car is 2 meters.

Initial speed of the car, u = 0

Let t is the time taken by the car . Using the second equation of motion as :

For vertical distance :

s=ut+\dfrac{1}{2}gt^2

t=\sqrt{\dfrac{2\times 2}{9.8}}=0.638\ s

Let v is the velocity to jump the stream. It is given by :

Horizontal distance, d = 5 m

v=\dfrac{5\ m}{0.638\ s}

v = 7.83 m/s

So, the car should travel with a speed of 7.83 m/s. Hence, this is the required solution.

8 0
4 years ago
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