Baseball, javelin, and maybe the clock but not sure on that... Just say baseball and javelin
Answer:
The energy stored in the spring would be 1 joule.
Explanation:
hope that helps?
Answer:
![x=\dfrac{r}{\sqrt2}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7Br%7D%7B%5Csqrt2%7D)
Explanation:
Given that
Radius =r
Electric filed =E
Q=Charge on the ring
The electric filed at distance x given as
![E=K\dfrac{Q}{(r^2+x^2)^{3/2}}](https://tex.z-dn.net/?f=E%3DK%5Cdfrac%7BQ%7D%7B%28r%5E2%2Bx%5E2%29%5E%7B3%2F2%7D%7D)
For maximum condition
![\dfrac{dE}{dx}=0](https://tex.z-dn.net/?f=%5Cdfrac%7BdE%7D%7Bdx%7D%3D0)
![E=K{Q}{(r^2+x^2)^{-3/2}}](https://tex.z-dn.net/?f=E%3DK%7BQ%7D%7B%28r%5E2%2Bx%5E2%29%5E%7B-3%2F2%7D%7D)
![\dfrac{dE}{dx}=K{Q}{(r^2+x^2)^{-3/2}}-\dfrac{3}{2}\times 2\times x\times K{Q}{(r^2+x^2)^{-5/2}}](https://tex.z-dn.net/?f=%5Cdfrac%7BdE%7D%7Bdx%7D%3DK%7BQ%7D%7B%28r%5E2%2Bx%5E2%29%5E%7B-3%2F2%7D%7D-%5Cdfrac%7B3%7D%7B2%7D%5Ctimes%202%5Ctimes%20x%5Ctimes%20K%7BQ%7D%7B%28r%5E2%2Bx%5E2%29%5E%7B-5%2F2%7D%7D)
For maximum condition
![\dfrac{dE}{dx}=0](https://tex.z-dn.net/?f=%5Cdfrac%7BdE%7D%7Bdx%7D%3D0)
![K{Q}{(r^2+x^2)^{-3/2}}-\dfrac{3}{2}\times 2\times x\times K{Q}{(r^2+x^2)^{-5/2}}=0](https://tex.z-dn.net/?f=K%7BQ%7D%7B%28r%5E2%2Bx%5E2%29%5E%7B-3%2F2%7D%7D-%5Cdfrac%7B3%7D%7B2%7D%5Ctimes%202%5Ctimes%20x%5Ctimes%20K%7BQ%7D%7B%28r%5E2%2Bx%5E2%29%5E%7B-5%2F2%7D%7D%3D0)
![r^2+x^2-3x^2=0](https://tex.z-dn.net/?f=r%5E2%2Bx%5E2-3x%5E2%3D0)
![x=\dfrac{r}{\sqrt2}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7Br%7D%7B%5Csqrt2%7D)
At
the electric field will be maximum.
1.cool down
2.activity log
3.specific warm up
4.activities of daily living
5.planned exercise
6.general warm up