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Fofino [41]
3 years ago
11

A force in the +x-direction has magnitude F = b/xn, where b and n are constants. For n > 1, calculate the work done on a part

icle by this force when the particle moves along the x-axis from x = x0 to infinity.
Physics
1 answer:
In-s [12.5K]3 years ago
3 0

Answer:

W=-\dfrac{b}{n-1}x_o^{1-n}

Explanation:

The magnitude of force in the +x direction is given by :

F=\dfrac{b}{x^n}

We need to find the work done. The integral form of work done is given by :

W=\int\limits {F.dx}

W=\int\limits^{\infty}_{x_{o}}{\dfrac{b}{x^n}.dx}

W=b \int\limits^{\infty}_{x_{o}}{\dfrac{1}{x^n}.dx}

W=b \int\limits^{\infty}_{x_{o}}{x^{-n}.dx}

W=\dfrac{bx^{1-n}}{1-n}|_{x_{o}}^\infty

W=-\dfrac{b}{n-1}x_o^{1-n}

Hence, this is the required solution.

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