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just olya [345]
2 years ago
14

How do you get hyphen notations?

Chemistry
1 answer:
laiz [17]2 years ago
6 0

Answer:

In hyphen notation, the mass number is written after the name of the element. For example, in isotopic notation, the isotope of carbon that has a mass number of twelve would be represented as 12C . In hyphen notation, it would be written as carbon-12.

Explanation:

lol just took the question and looked it up online this was the first thing that i saw if its not correct im sorry

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Answer:

According to Hund's rule and the Aufbau principle in which the orbitals must be filled with electrons, they are not strictly applied in the real universe, because the intermediate and electron-filled atomic orbitals are very stable . Because there are four d-orbitals in universe L, a typical half-full configuration will be xd4 and its full configuration will be xd8, where x is the primary orbital for any specific element. Here is an example:

Vahadium ₂₃V

in real universe: [Ar]₈ 3d³4s²

in universe L: [Ar]₁₈ 3d⁴4s¹

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in real universe: [Ar]₈ 3d⁵4s¹

in universe L: [Ar]₁₈ 3d⁴4s²

Explanation:

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3 years ago
Which type of volcano formation would typically be found under a convergent boundary?
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A chain volcano would be my answer
6 0
3 years ago
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Why an offspring and its parent share many common traits?
blondinia [14]

Answer:

Explanation: Traits are characteristics, such as its size or height and that comes from parents or other relatives.

3 0
2 years ago
A chunk of tin weighing 18.5 grams and originally at 97.38 °C is dropped into an insulated cup containing 75.7 grams of water at
weqwewe [10]

Answer:

22.44°C will be the final temperature of the water.

Explanation:

Heat lost by tin will be equal to heat gained by the water

-Q_1=Q_2

Mass of tin = m_1=18.5 g

Specific heat capacity of tin = c_1=0.21 J/g^oC

Initial temperature of the tin = T_1=97.38^oC

Final temperature = T_2=T

Q_1=m_1c_1\times (T-T_1)

Mass of water= m_2=75.7 g

Specific heat capacity of water= c_2=4.184 J/g^oC

Initial temperature of the water = T_3=21.52^oC

Final temperature of water = T_2=T

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

-(18.5 g\times 0.21 J/g^oC\times (T-97.38^oC))=75.7 g\times 4.184 J/g^oC\times (T-21.52 ^oC)

we get, T = 22.44°C

22.44°C will be the final temperature of the water.

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3 years ago
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