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Alina [70]
3 years ago
8

Which is a diatomic molecule? A. He B. O2 C. NaCl D. CuF2

Chemistry
2 answers:
Alex3 years ago
6 0

Answer:

O2

Explanation:

katrin2010 [14]3 years ago
4 0

O2 is the right answer                      

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Answer: As sea levels rise, coastal communities will lose land and possibly see damages in infrastructure if the levels rise high enough

7 0
2 years ago
A student mixes some water at room temperature with a white powder also at room temperature. The white powder disappears into th
Leya [2.2K]
Chemical change, because the white powder heated the water and caused a thermal reaction, and possibly gas was produced due to bubbles.
5 0
2 years ago
What mass of magnesium chloride is needed to make 100.0 mL of a solution that is 0.500 M in chloride ion?
miss Akunina [59]
M = n/V

.5M = n/.100 L

n = .1 L * .5M

n= .05 mols of MgCl2

mass of MgCl2 = .05 mols of MgCl2 * 95.211 grams/ 1 mol of MgCl2 

mass of MgCl2 = 4.76 grams

4.76 grams of MgCl2 is needed to make 100 ml of a solution that is .500M, in chloride ion. Bolded = confused
3 0
3 years ago
Gabriella weighs 450 N. She climbs a flight of stairs to a height of 3 m. It takes her 5 seconds. How much work does Gabriella d
Flura [38]

The formula that can be applied in this problem is W = Fd where W is work, F is the force and d is distance. You have 450N and 3m, all you have to do is to multiply it.

W = Fd

W = (450N) (3m)

W = 1350J

The answer is letter C.

6 0
3 years ago
Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu
Svet_ta [14]

Answer:

V_1=23.3~mL

Explanation:

In this case, we have a dilution problem. We have to remember that in the dilution procedure we go from a solution with higher concentration to a solution with lesser concentration. Therefore we have to start with the dilution equation:

C_1*V_1=C_2*V_2

Now we can identify the variables:

C_1=~1.475_M

V_1=~?

C_2=~0.1374_M

V_2=~250.0~mL

If we plug all the values into the equation:

1.475_M*V_1=0.1374_M*250.0~mL

And we solve for V_1:

V_1=\frac{0.1374_M*250.0~mL}{1.475_M}

V_1=23.3~mL

I hope it helps!

8 0
2 years ago
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