Number of electrons transferred: 
Explanation:
The charge on the first object is

while the charge on the 2nd object is

When they are in contact, the final charge on each object will be

So, the amount of charge (electrons) transferred from the 1st object to the 2nd object is

The charge of one electron is

Therefore, the number of electrons transferred is

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<em><u>The</u></em><em><u> </u></em><em><u>force</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>gravity</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>positive</u></em><em><u> </u></em><em><u>9</u></em><em><u>.</u></em><em><u>8m</u></em><em><u>/</u></em><em><u>s</u></em><em><u>^</u></em><em><u>2</u></em><em><u>.</u></em>
Answer:
Before:


After:




Explanation:
<u>Conservation of Momentum</u>
Two objects of masses m1 and m2 moving at speeds v1o and v2o respectively have a total momentum of

After the collision, they have speeds of v1f and v2f and the total momentum is

Impulse J is defined as

Where F is the average impact force and t is the time it lasted
Also, the impulse is equal to the change of momentum

As the total momentum is conserved:


We can compute the speed of the second object by solving the above equation for v2f

The given data is


a) The impulse will be computed at the very end of the answer
b) Before the collision


c) After collision

Compute the car's speed:


And the car's momentum is

The Impulse J of the system is zero because the total momentum is conserved, i.e. \Delta p=0.
We can compute the impulse for each object

The force can be computed as

The force on the car has the same magnitude and opposite sign
Answer:
26.67 m/s
Explanation:
From the law of conservation of linear momentum, the initial sum of momentum equals the final sum.
p=mv where p is momentum, m is the mass of object and v is the speed of the object
Initial momentum
The initial momentum will be that of basketball and volleyball, Since basketball is initially at rest, its initial velocity is zero

Final momentum

Answer:
161.86 N
Explanation:
mass of box m= 55.0 kg
weight of the box, mg= 55×9.81
g here is acceleration due to gravity =9.81 m/sec^2
coefficient of friction between the box and the surface μ= 0.3
the friction force F_s= μmg= 0.3×55×9.81
=161.86 N
to move the ball horizontal force required is 161.86 N