Answer:
t = 1030 s
Explanation:
Let's start by calculating the resistance of the coil,
V = I (R + ri)
R = V / I - ri
R = 10/10 -0.03
R = 0.97 Ω
Now we can calculate the power supplied to the water
P = I2 R
P = 10 2 0.97
P = 97 w
Work energy is power for time
E = W = P t
t = W / P
t = 100 103/97
t = 1030 s
First, let's determine the gravitational force of the Earth exerted on you. Suppose your weight is about 60 kg.
F = Gm₁m₂/d²
where
m₁ = 5.972×10²⁴ kg (mass of earth)
m₂ = 60 kg
d = 6,371,000 m (radius of Earth)
G = 6.67408 × 10⁻¹¹ m³ kg⁻¹ s⁻²
F = ( 6.67408 × 10⁻¹¹ m³ kg⁻¹ s⁻²)(60 kg)(5.972×10²⁴ kg)/(6,371,000 m )²
F = 589.18 N
Next, we find the gravitational force exerted by the Sun by replacing,
m₁ = 1.989 × 10³⁰<span> kg
Distance between centers of sun and earth = 149.6</span>×10⁹ m
Thus,
d = 149.6×10⁹ m - 6,371,000 m = 1.496×10¹¹ m
Thus,
F = ( 6.67408 × 10⁻¹¹ m³ kg⁻¹ s⁻²)(60 kg)(1.989 × 10³⁰ kg)/(1.496×10¹¹ m)²
F = 0.356 N
Ratio = 0.356 N/589.18 N
<em>Ratio = 6.04</em>
Answer:
E
Explanation:
From the equation describing the Electric field strength of a charge
E=F/q
We can deduce that the electric field strength is dependent on the force arcing on the magnitude of the charge.
As the force increases the the electric field increases, also the electric field strength decreases with increasing charge.
Hence the distance has no effect on the electric field strength. The magnitude remain as E
Answer:
A parallel circuit has two or more paths for current to flow through.
Voltage is the same across each component of the parallel circuit.
The sum of the currents through each path is equal to the total current that flows from the source.
Explanation:
