Question

4y-12x+8=0; Solve for y

Answer 1

$4y-12x+8=0$

$4y = 12x-8$

$y = 3x - 2$

Answer 2

$4y-12x+8=0\ \ \ \ /+12x\\\\4y+8=12x\ \ \ \ /-8\\\\4y=12x-8\ \ \ \ /:4\\\\y=\frac{12x}{4}-\frac{8}{4}\\\\y=3x-2$