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3 years ago

F(x) is a function. A. True B. False

Mathematics

2 answers:

pogonyaev3 years ago

7 0

I’m pretty sure it’s true

lina2011 [118]3 years ago

4 0

Answer:

True, this is a function

Step-by-step explanation:

There is a 1 to one correspondence between x and y

Each x goes to one y, so this is a function

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Write the numbers in order from least to greatest<br><br> 1.3, 1 1/3, 1.34

Norma-Jean [14]

Answer:

1.3, 2 1/3, 1.34 is the order from least to greatest

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3 years ago

The length of a rectangle is represented by the polynomial 2x3 – 5x2 + 8 and the width is represented

Rom4ik [11]

1) the polynomial representing the area is

2x^4 + 6x^3 - 5x^2 -7x + 24

2) the constant term is

3) the polynomial is a 4th degree

4) if my guess is ryt... the LEADING coefficient is the coefficient of the highest degree of X ...i.e 2

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3 years ago

Read 2 more answers

Hey, I really need some help figuring out this question.

Alexandra [31]

Answer:

it's d

Step-by-step explanation:

because the answer would be the same on both sides

6 0

2 years ago

The governor of Utah wants to know how long they have before the entire state is zombified. If there are 3.67 million people liv

Bingel [31]

Answer:

wait.

Step-by-step explanation:

what do u really mean by zombies

6 0

3 years ago

Given cosα = −3/5, 180 < α < 270, and sinβ = 12/13, 90 < β < 180

torisob [31]

I got

$- \frac{6 3}{65}$

What we know

cos a=-3/5.

sin b=12/13

Angle A interval are between 180 and 270 or third quadrant

Angle B quadrant is between 90 and 180 or second quadrant.

What we need to find

Cos(b)

Cos(a)

What we are going to apply

Sum and Difference Formulas

Basics Sine and Cosines Identies.

1. Let write out the cos(a-b) formula.

$\cos(a - b) = \cos(a) \cos(b) + \sin(a) \sin(b)$

2. Use the interval it gave us.

According to the given, Angle B must between in second quadrant.

Since sin is opposite/hypotenuse and we are given a sin b=12/13. We. are going to set up an equation using the pythagorean theorem.

${12}^{2} + {y}^{2} = {13}^{2}$

$144 + {y}^{2} = 169$

$25 = {y}^{2}$

$y = 5$

so our adjacent side is 5.

Cosine is adjacent/hypotenuse so our cos b=5/13.

Using the interval it gave us, Angle a must be in the third quadrant. Since cos is adjacent/hypotenuse and we are given cos a=-3/5. We are going to set up an equation using pythagorean theorem,

$( - 3) {}^{2} + {x}^{2} = {5}^{2}$

$9 + {x}^{2} = 25$

${x}^{2} = 16$

$x = 4$

so our opposite side is 4. sin =Opposite/Hypotenuse so our sin a =4/5.Sin is negative in the third quadrant so

sin a =-4/5.

Now use cosine difference formula

$- \frac{3}{5} \times \frac{5}{13} + - \frac {4}{5} \times \frac{12}{13}$

$- \frac{15}{65} + ( - \frac{48}{65} )$

$- \frac{63}{65}$

Hope this helps

6 0

2 years ago