This question is incomplete, the complete question is;
A driver takes 3.5 s to react to a complex situation while driving at a speed of 60 mi/h.
How far does the vehicle travel before the driver initiates a physical response to the situation (i.e., putting his or her foot on the brake)
Answer:
the distance travelled by the vehicle, before the driver initiates a physical response is 308 ft
Explanation:
Given that;
Reaction time t = 3.5 sec
Speed S = 60 mi/h
we convert mile to foot and hour to seconds
so
Speed S = 60 mi/h = (60×5280)/(60×60) = 316800/3600 = 88 ft/sec
Now, The distance travelled by vehicle before the driver initiates physical response is equal to Lag distance. i.e
Lag distance = V × t
we substitute
Lag distance = 88 ft/sec 3.5 sec
Lag distance = 308 ft
Therefore, the distance travelled by the vehicle, before the driver initiates a physical response is 308 ft
Answer:
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Explanation:
just I'm a practice <u>to-day</u>
Answer:
The package will be directly below the location of the plane.
Explanation:
Look up projectile motion for more information. The horizontal speed of the package is separate from the vertical speed of the package. The vertical speed of the falling package will be based on the rate of acceleration and the height of the package when dropped. The horizontal speed of the package will be the same as the plane so the package will remain directly below the plane the entire time until the package hits the ground.
Answer:
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They hit at the same time. Everything falls at the same rate.