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solmaris [256]
2 years ago
11

Beloved Baby Company manufactures and sells children's strollers. Each stroller requires eight screws. For September, Beloved Ba

by Company will begin September with 380 screws in its beginning inventory, and budgets ending inventory to be 210. Beloved Baby Company has budgeted stroller sales of 530 strollers, while 570 strollers are scheduled to be produced. How many screws should Beloved Baby Company purchase in September? O A. 4,560 B. 150 O C. 4,94 O D. 4,390
Business
1 answer:
ololo11 [35]2 years ago
8 0

Answer:

The correct answer is D.

Explanation:

Giving the following information:

Each stroller requires eight screws. For September, Beloved Baby Company will begin September with 380 screws in its beginning inventory, and budgets ending inventory to be 210. Beloved Baby Company has budgeted stroller sales of 530 strollers, while 570 strollers are scheduled to be produced

Production= 570*8= 4560

Ending inventory= 210

Beginning inventory= 380 (-)

Total= 4,390

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drek231 [11]

Answer:

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Explanation:

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6 0
3 years ago
What reasons would you give for the reaction of consumers to price changes​
zloy xaker [14]

Answer:

At first, the consumer might think that the watch might be more exclusive than before. Or consumer also might think that the company is so greedy to get more profits. Similarly, if the company cutting off price may have the negative impact on the consumer mind.

Uh yes my answer

Explanation:

7 0
2 years ago
Read 2 more answers
On December 15, 2021, Rigsby Sales Co. sold a tract of land that cost $3,300,000 four $5,000,000. Rigsby appropriately uses the
Flura [38]

<u>Solution and Explanation:</u>

Installment Receivables (Net) of $2,905,600

Basis  Particulars                                         Debit  Credit

Sale:-  Instalment Receivables  $5,000,000  

         Inventory                                               $3,200,000

 Deferred gross profit                                                  $1,800,000

Payment:-  Cash                         $4,90,000  

Instalment Receivables                                     $4,90,000

Deferred Gross profit                 $165,600  

Realised Gross profit                                              $165,600

Instalment Receivables ($5,000,000 minus $490,000) = $4,510,000

Deferred gross profit ($1,800,000 minus $165,600) = $1,634,400

Instalment Receivables (Net) = $2,875,600

8 0
3 years ago
Problem 3.22: Trade Deficits and J-curve Adjustment Path Assume the United States has the following import/export volumes and pr
Sergio039 [100]

Answer:

The pre-devaluation cost is ($880) and the pst-devaluation trade balance is ($1398)

Explanation:

Assumptions Values

Initial spot exchange rate, $/fc $2.00

Price of exports, dollars ($) * 20.0000

Price of imports, foreign currency (fc) * 12.0000

Quantity of exports, units * 100

Quantity of imports, units * 120

Percentage devaluation of the dollar 18.00%

Price elasticity of demand, imports * (0.900)

a. The pre-devaluation trade balance--

Revenues from exports, $ $2,000

Expenditures on imports, fc * 1,440

Expenditures on imports, $ $2,880

Pre-devaluation trade balance ($880)

b. Resulting trade balance immediately after devaluation

Revenues from exports, $ $2,000

Expenditures on imports, fc * 1,440

New spot exchange rate, after devaluation $2.36

Expenditures on imports, $ $3,398

Post-devaluation trade balance (currency contract period) ($1,398)

8 0
3 years ago
Suppose 20.0 g pieces of gold and iron, both initially at 100oC, are added to different containers of water, both initially at 2
Sauron [17]

Answer:

  • The final temperature in the container with Gold is 27.49 ⁰C
  • The final temperature in the container with Iron is  33.01  ⁰C

Therefore, the highest final temperature is obtained in the container with Iron.

Explanation:

Q = mcΔT

Where;

Q is the quantity of heat gained or lost

m is the mass of the metals or water

c is the specific heat capacity

ΔT is the change in temperature, T₂ - T₁

T₂  is the final temperature and T₁ is the initial temperature

Heat lost by metals at 100°C is equal to heat gained by water at 25°C

-Q_{metal} = Q_{water}

-Q_{Au} = Q_{H_2O} \\-Q_{Fe}  = Q_{H_2O}

Specific heat capacity of water = 4.18 J/g°C

Specific heat capacity of gold = 0.129 J/g°C

Specific heat capacity of iron  = 0.45 J/g°C

⇒For Gold

-20*0.129*(T₂ - 100) = 18*4.18 (T₂ - 25)

-2.58T₂ +258 = 75.24T₂  - 1881

77.82T₂  = 2139

T₂  = 2139/77.82

T₂ = 27.49 ⁰C

⇒For Iron

-20*0.450*(T₂ - 100) = 18*4.18 (T₂  - 25)

-9T₂  +900 = 75.24T₂ - 1881

84.24T₂ = 2781

T₂  = 2781/84.24

T₂ = 33.01  ⁰C

Therefore, the highest final temperature is obtained in the container with Iron.

5 0
3 years ago
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