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labwork [276]
2 years ago
10

10) The amount of money, A, accrued at the end of n years when a certain amount, P, is invested at a compounded

Mathematics
1 answer:
aleksandrvk [35]2 years ago
6 0
Total = 350.00 * (1.02)^5
Total = 350.00 * <span> <span> <span> 1.1040808032 </span> </span> </span>
Total = 386.43


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jok3333 [9.3K]

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2 years ago
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How to algebraically find the limit of a function as x approaches infinity?
Sauron [17]

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3 years ago
Please helppp 15 pointsss What is the y-coordinate of the solution for the system of equations?
Lina20 [59]

y = 3x - 1

x - y = -9


Subs y in second equation.


x - (3x - 1) = -9

x - 3x + 1 = -9

-2x = -9 - 1

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x = -10/-2

x = 5


Subs x


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y = 14


7 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E%7B2%7D-1%7D%7B2-5a%7D%20times%20%5Cfrac%7B15a-6%7D%7Ba%5E%7B2%7D%2B5a-6%7D" id=
stepan [7]
\bf \cfrac{a^2-1}{2-5a}\times \cfrac{15-6}{a^2+5a-6}\\\\&#10;-----------------------------\\\\&#10;recall\quad \textit{difference of squares}&#10;\\ \quad \\&#10;(a-b)(a+b) = a^2-b^2\qquad \qquad &#10;a^2-b^2 = (a-b)(a+b)\\\\&#10;thus\quad a^2-1\iff a^2-1^2\implies (a-1)(a+1)&#10;\\\\\\&#10;now\quad a^2+5a-6\implies (a+6)(a-1)\\\\&#10;-----------------------------\\\\&#10;thus&#10;\\\\\\&#10;\cfrac{a^2-1}{2-5a}\times \cfrac{15-6}{a^2+5a-6}\implies \cfrac{(a-1)(a+1)}{2-5a}\times \cfrac{3(5a-2)}{(a+6)(a-1)}\\\\&#10;-----------------------------\\\\&#10;

\bf now\quad 3(5a-2) \iff -3(2-5a)\\\\&#10;-----------------------------\\\\&#10;thus&#10;\\\\\\&#10;\cfrac{\underline{(a-1)}(a+1)}{\underline{2-5a}}\times \cfrac{-3\underline{(2-5a)}}{(a+6)\underline{(a-1)}}\implies \cfrac{-3(a+1)}{a+6}
6 0
3 years ago
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