<h2>
Hey There!</h2><h2>
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Answer:</h2>
<h2>_____________________________________</h2><h3>DATA:</h3>
Radius of Mercury = =
Mass of Mercury =
Distance Satellite above the surface of the Mercury = d = 265,000m
Gravitational Constant =
<h2>_____________________________________</h2><h3>SOLUTION:</h3>
Since the Satellite is orbiting around the Planet Mercury, due to the centripetal force, and Centripetal force is the force that acts towards the center of the circle, Whereas The gravitational force also acts towards the center of the circle thus we can say that Centripetal force is equal or same as centripetal force. So,
Fg is Given by,
Fc is Given by,
Where,
G is Gravitational Constant
is mass of Planet Mercury
is Mass of Satellite
r(small letter) is the distance between the center of the Planet Mercury and the satellite.
V is velocity of satellite
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Now,
r can also be written as,
Substitute the variables,
Simplify the equation,
V = 2814
Approximately,
V = 2800
<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h3 />
Answer:
Explanation:
Given
Fundamental Frequency(f) is 50 Hz
and frequency is given by
Where T= tension
=mass per unit length
if tension is doubled
Divide 1& 2
Small objects vibrate quickly and produce lots of waves each second, and as the length of the bells are short the wave length become short too,so small bells have a high frequency hence high pitch.