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Flura [38]
3 years ago
15

rectangular plate, whose streamwise dimension (or chord c) is 0.2 m and whose width (or span b) is 1.8 m, is mounted in a wind t

unnel. The freestream velocity is 40 m/s. The density of the air is 1.2250 kg/m3, and the absolute viscosity is 1.7894 x 10-5 kg/m s. Plot (not sketch) the velocity profiles at x = 0.0 m, x = 0.05 m, x = 0.10 m, and x = 0.20 m. Calculate the chordwise distribution of the skin friction coefficient and the displacement thickness. What is the drag coefficient for the plate? Be sure to account for both sides of the plate. Ans.: CD = 3.587 x 10

Physics
1 answer:
Andrei [34K]3 years ago
8 0

Answer:

See explaination for the details of the answer.

Explanation:

Density is a measurement that compares the amount of matter an object has to its volume. An object with much matter in a certain volume has high density An object with little matter in the same amount of volume has a low density. Density is found by dividing the mass of an object by its volume.

The Calculate of the chordwise distribution of the skin friction coefficient and the displacement thickness is done and represented in the attachment.

Please kindly check attachment for the step by step answer.

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Ned tightens a bolt in his car engine by exerting 15 N of force on his wrench at a distance of 0.45m from the fulcrum. How much
____ [38]

Answer:

T = 6.75\,N\cdot m

Explanation:

Vectorially speaking, torque is the cross product between force and distance from fulcrum. Its magnitude is equal to the following expression:

T = F\cdot r \cdot \sin \theta

T = F_{\bot} \cdot r

Let assume that force is perpendicular to the distance from the fulcrum. So, the torque needed to turn the bolt is:

T = (15\,N)\cdot (0.45\,m)

T = 6.75\,N\cdot m

8 0
4 years ago
a spotted lizard runs at 3m/s at top speed. a girl wants to catch the lizard to keep as a pet. where should the girl place her c
Ann [662]

The acceleration due to earth's gravity is -9.8 m/s [dn] I thought... I'm assuming this is a projectile motion question asking for the range.

Break each kinematic quantity into their x and y components.

          x           y

v₁ = 3 m/s        0

v₂ = 3 m/s        ?

Δd = ?            -1.5

Δt  = ?              ?

a = 0           -10 m/s²

So the variable we are trying to find is Δdx (x component of displacement). We need to use a kinematic equation to do so. However, we obviously don't have enough given to find Δdx. This means we need to find something first, something we can use. How about Δt? Δt can be applied to both the x and y components. We have enough information in the y component list to find Δt. We can use this formula and solve for Δt.

Δdy = v₁y ( Δt ) + 1/2 ( ay ) ( Δt )²

Δdy = 1/2 ( ay ) ( Δt )²   <- the first term cancels out since v₁y = 0.

2Δdy = ay ( Δt )²

2Δdy / ay = ( Δt )²

√ 2Δdy / ay = Δt

√ 2(-1.5 m/s) / -9.8 m/s² = Δt

√ -3.0 m/s / -9.8 m/s² = Δt

√ 0.3<u>0</u>6122449 s² = Δt

0.5<u>5</u>32833352 s = Δt

Now, we can use this newly found quantity to solve for Δdx using the x component values using the appropriate kinematic equation.

Δdx = ( v₁x + v₂x / 2) ( Δt )

Δdx = ( ( 3.0 m/s + 3.0 m/s ) / 2 ) ( 0.5<u>5</u>32833352 s )

Δdx = ( 6.0 m/s / 2 ) ( 0.5<u>5</u>32833352 s )

Δdx = ( 3.0 m / s )( 0.5<u>5</u>32833352 s )

Δdx = 1.<u>6</u>59850006 m

Therefore, the girl should place her cage 1.7 m away from the platform to catch the lizard.

This solution assumes that the acceleration due to gravity is -10 m/s² [dn] and not -9.8 m/s² [dn]. If you need -9.8 m/s² [dn], then just substitute it into my solution. This was a pain to type lol





6 0
3 years ago
Calculate the work done by applying a 125 N force to the right on a 65.0 kg sled to displace
Elanso [62]
W=fd
W= (125N) (3.5m)
W= 437.5 J
5 0
3 years ago
What is the acceleration of a car that goes from zero to 40 m/s in 20 seconds
Ahat [919]
A=v-u/t
a=40-0/20
a=40/20
a=2m/s^2
3 0
3 years ago
The Golden Gate Bridge in San Francisco has a main span of length 1.28 km, one of the longest in the world. Imagine that a steel
Valentin [98]

Answer:

361.46 N

Explanation:

\alpha = Coefficient of thermal expansion = 11\times 10^{-6}\ /^{\circ}C

Y = Young's modulus for steel = 20\times 10^{10}\ Pa

A = Area = 3.1\times 10^{-6}\ m^2

L_0 = Original length = 1.28 km

\Delta T = Change in temperature = 45-(-10)

Length contraction is given by

\Delta L=\alpha L_0\Delta T

Also,

\Delta L=\dfrac{L_0T}{YA}

\alpha L_0\Delta T=\dfrac{L_0T}{YA}\\\Rightarrow T=\alpha \Delta TYA\\\Rightarrow T=11\times 10^{-6}\times (43-(-10))\times 20\times 10^{10} \times 3.1\times 10^{-6}\\\Rightarrow T=361.46\ N

The tension in the wire is 361.46 N

4 0
3 years ago
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