Answer:
w = 0.00098 N
Explanation:
Given data:
Acceleration = 9.80 m/s²
Mass of honey = 0.0001 Kg
weight = ?
Solution:
Formula:
w = mg
w = weight
m = mass
g = acceleration due to gravity
Now we will put the values in formula:
w = 0.0001 Kg × 9.80 m/s²
w = 0.00098 N
339 grams of CLF3 is formed when F2 is in excess and 130 grams of CL2 reacts.
Explanation:
The balanced chemical reaction for the formation of ClF3 is given by:
+ 3 ⇒ 2 Cl
the mass of Cl2 is given 130 grams
From the equation it is found that 2 moles of chloride reacts to form 2 moles of ClF3.
calculating the number of moles of chlorine by the formula:
Number of moles = mass of the substance ÷ atomic mass of one mole of the substance
n = 130 ÷ 35.45
= 3.6671 moles
So, applying stoichiometry
2 moles of Cl2 formed 2 moles of ClF3
3.6671 moles of Cl2 will form x moles of ClF3
2 ÷ 2 = x ÷ 3.6671
x = 3.6671 moles of ClF3
now from the formula of number of moles
weight is calculated as n × mass of the gas
3.6671 × 92.448
= 339.01 grams of ClF3 is formed.
Answer:
None
Explanation:
Heyyy,,,,,,,,,,,, hi..........
Delta E = Ef - Ei
E = energy , h = plank constant , v = frequency
h= 6.626 * 10 ^-34 j*s , T = 10 ^ 12 , v = 74 * 10 ^12 Hz , Hz = s^-1
E = ( 6.626 * 10^ -34 j*s) ( 74 * 10 ^ 12 s^ -1 ) = 4.90 * 10 ^ -20 J
Delta E = Ef - Ei
-4.90 * 10 ^ -20 J = -2.18 * 10 ^ -18J ( 1/4 ^2 - 1/x ^2)
0.0225 = 0.0625 - ( 1/x ^ 2)
0.225 - 0.0625 = - 1/ x ^ 2
- 0.0400 = - 1/x ^2 = -1 / - 0.0400 = x^2
25 = x^2
x = 5
So when given a chemical formula, the subscripts directly in front of the atom correspond to the amount of atoms in that compound. So we have .
There's a 2 in front of hydrogen (H), so there are 2 atoms of Hydrogen.
There are no numbers in front of sulfur (S), so it is assumed to be 1.
There is a 4 in front of oxygen (O), so there are 4 atoms of oxygen present.
So overall, the answer is D) 2 hydrogen atoms, 1 sulfur atom, and 4 oxygen atoms.