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lukranit [14]
3 years ago
6

7. How many grams of CIF3 form from 130.0 grams of Cl2 when F2 is in excess?

Chemistry
1 answer:
Gnoma [55]3 years ago
3 0

339 grams of CLF3 is formed when F2 is in excess and 130 grams of CL2 reacts.

Explanation:

The balanced chemical reaction for the formation of ClF3 is given by:

Cl_{2} + 3 F_{2} ⇒ 2 ClF_{3}

the mass of Cl2 is given 130 grams

From the equation it is found that 2 moles of chloride reacts to form 2 moles of ClF3.

calculating the number of moles of chlorine by the formula:

Number of moles = mass of the substance ÷ atomic mass of one mole of the substance

n = 130 ÷ 35.45

   = 3.6671 moles

So, applying stoichiometry

2 moles of Cl2 formed 2 moles of ClF3

3.6671 moles of Cl2 will form x moles of ClF3

2 ÷ 2 = x ÷ 3.6671

x = 3.6671 moles of ClF3

now from the formula of number of moles

weight is calculated as n × mass of the gas

                                    3.6671 × 92.448

                                    =  339.01 grams of ClF3 is formed.

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Electronic configuration: The distribution or arrangement of electrons of a molecule or an atom in molecular or atomic orbitals.

Ground state electron configuration: The distribution of electrons of an atom or molecule around the nucleus with lower levels of energy.

Now, Ru stands for Ruthenium with atomic number 44. It is a metal and thus, has ability to lose electrons and, becomes positively charged ion.

One can write the electronic configuration with the help of atomic number and Afbau principle, Pauli exclusion principle etc.

Ground electronic Configuration is as follows:

Ru = s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{1}4d^{7}

Soft Hand notation: [Kr]4d^{7}5s^{1}

Now, when ruthenium loses two electrons then it becomes Ru^{+2}, thus electron configuration becomes

Soft Hand notation: [Kr]4d^{6}

The ground state electronic configuration of Ruthenium is [Kr]4d^{7}5s^{1} and when it loses two electrons, then electronic configuration becomes [Kr]4d^{6} ( Ru^{+2})





5 0
3 years ago
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The molarity of a 4.200 L solution is 1.230 M Na2CO3. What is the mass of Na2CO3
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Answer:

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Explanation:

To get the mass, you need moles.

moles = (molarity)(Liters)

moles = (1.230M)(4.200L) = 5.166 moles Na2CO3

Now, just use stoichiometry

molar mass of Na2CO3 = 2(mass of Na) + (mass of C) + 3(mass of O)

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5.166moles(105.99g/mol)

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But, the measurements given had 4 significant figures, so in chemistry we write:

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4 years ago
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tester [92]

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Explanation:

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Mass of hydrogen + mass of oxygen = Mass of water

Therefore;

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