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3 years ago

7

an object tied to the end of the string moves in a circle . the force exerted by the string depends on the mass of the object it

's speed and radius of the circle what combination of these variables gives the correct dimensions (ML/T) for the force

1 answer:

otez555 [7]3 years ago

6 0

Answer:Fc=mv^2/r

Explanation:

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Answer the following. (a) What is the surface temperature of Betelgeuse, a red giant star in the constellation of Orion, which r

bagirrra123 [75]

Answer:

(a) T = 2987.6 k

(b) T = 19986.2 k

Explanation:

The temperature of a star in terms of peak wavelength can be given by Wein's Displacement Law, which is as follows:

$T = \frac{0.2898\ x\ 10^{-2}\ m.k}{\lambda_{max}}$

where,

T = Radiated surface temperature

$\lambda_{max}$ = peak wavelength

(a)

here,

$\lambda_{max}$ = 970 nm = 9.7 x 10⁻⁷ m

Therefore,

$T = \frac{0.2898\ x\ 10^{-2}\ m.k}{9.7\ x\ 10^{-7}\ m}$

<u>T = 2987.6 k</u>

(b)

here,

$\lambda_{max}$ = 145 nm = 1.45 x 10⁻⁷ m

Therefore,

$T = \frac{0.2898\ x\ 10^{-2}\ m.k}{1.45\ x\ 10^{-7}\ m}$

<u>T = 19986.2 k</u>

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2 years ago

What do radio waves and microwaves have in common?

MAVERICK [17]

#3, they both come after infared and are not harmful to living cells.

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3 years ago

Explain, briefly, what the electrical field inside a microwave oven does to heat food.

yarga [219]

Answer:

Inside the strong metal box, there is a microwave generator called a magnetron. When you start cooking, the magnetron takes electricity from the power outlet and converts it into high-powered, 12cm (4.7 inch) radio waves. Thus the microwaves pass their energy onto the molecules in the food, rapidly heating it up.May 3, 2018

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2 years ago

Jess rides her motorcycle at an average speed of 20 m/s for 500 seconds. how far did she ride

Sedaia [141]

Distance = (speed) x (time)

Distance = (20 m/s) x (500 s)

Distance = (20 x 500) (m·s / s)

Distance = 10,000 m

5 0

2 years ago

Find the wavelength of the third line in the lyman series, and identify the type of em radiation.

Natalija [7]

The wavelength of the third line in the Lyman series, and identify the type of EM radiation

In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (n=2,3,4,5... ). The wavelength of light emitted in this series lies in the ultraviolet region of the electromagnetic spectrum.

1 / lambda = R(h)* ( $\frac{1}{(n1)^{2} }$ - $\frac{1}{(n2)^{2} }$ )

= 109678 ( $\frac{1}{1^{2} }$ - $\frac{1}{3^{2} }$ )

= 109678 (8/9)

Lambda = 9 / (109678 * 8 )

= 102.6 * $10^{-9}$ m = 102.6 nm

To learn more about Lyman series here

brainly.com/question/5762197

#SPJ4

8 0

1 year ago