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3 years ago

What is the difference between a proton, neutron, and electron?

Chemistry

1 answer:

jok3333 [9.3K]3 years ago

7 0

Answer:

proton :

a particale or atom containing a postive charge

nuutron

a particale or atom that contains a negative charge

electron :

a particale or atom with a negative chrage.

Explanation:

proton:

a stable subatomic particle occurring in all atomic nuclei, with a positive electric charge equal in magnitude to that of an electron, but of opposite sign.

nuetron:

a subatomic particle of about the same mass as a proton but without an electric charge, present in all atomic nuclei except those of ordinary hydrogen.

elcetron:

a stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.

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a balloon is filled with 3.60 L of H2 gas at STP. If the balloon is taken into the sea where the pressure is 2.50 atm and the te

kherson [118]

The new volume of the hydrogen gas in the balloon is 1.5 L.

<u>Explanation:</u>

At STP, Temperature, T1 is 0° C = 0 + 273 K = 273 K

Pressure, P1 = 1 atm

Here given volume, V1 = 3.60 L

Balloon at sea,

Pressure, P2 = 2.5 atm

Temperature, T2 = 10° C = 10 + 273 = 283 K

Volume, V2 = ?

Here, we have to use the equation,

$$\frac{P1V1}{T1} = \frac{P2V2}{T2}$

We have to rearrange the equation to get V2 as,

$$V2 = \frac{P1V1T2}{T1P2}$

Now plugin the values as,

V2 = $$\frac{1 atm \times 3.6 L \times 283 K}{273 K \times 2.5}$

= 1.5 L

So the new volume of the hydrogen gas is 1.5 L.

7 0

4 years ago

Read 2 more answers

The vapor pressure of water at 80 °C is 355.3 torr. Calculate the vapor pressure in mm Hg and atm. Be sure your answers have the

Darya [45]

Answer:

0.4675 atm, 355.3 mmHg

Explanation:

Given:

Pressure = 355.3 torr

The conversion of P(torr) to P(atm) is shown below:

$P(torr)=\frac {1}{760}\times P(atm)$

So,

Pressure = 355.3 / 760 atm = 0.4675 atm

The conversion of P(torr) to P(mmHg) is shown below:

$P(torr)=1\times P(mmHg)$

So,

Pressure = 355.3 mmHg

8 0

3 years ago

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol. In the presence of a catalyst at 37°C, the r

rodikova [14]

Answer:

E₁ ≅ 28.96 kJ/mol

Explanation:

Given that:

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol,

Let the activation energy for a catalyzed biochemical reaction = E₁

E₁ = ??? (unknown)

Let the activation energy for an uncatalyzed biochemical reaction = E₂

E₂ = 50.0 kJ/mol

= 50,000 J/mol

Temperature (T) = 37°C

= (37+273.15)K

= 310.15K

Rate constant (R) = 8.314 J/mol/k

Also, let the constant rate for the catalyzed biochemical reaction = K₁

let the constant rate for the uncatalyzed biochemical reaction = K₂

If the rate constant for the reaction increases by a factor of 3.50 × 10³ as compared with the uncatalyzed reaction, That implies that:

K₁ = 3.50 × 10³

K₂ = 1

Now, to calculate the activation energy for the catalyzed reaction going by the following above parameter;

we can use the formula for Arrhenius equation;

$K=Ae^{\frac{-E}{RT}}$

If $K_1=Ae^{\frac{-E_1}{RT}} -------equation 1$ &

$K_2=Ae^{\frac{-E_2}{RT}} -------equation 2$

$\frac{K_1}{K_2} = e^{\frac{-E_1-E_2}{RT}$

$E_1= E_2-RT*In(\frac{K_1}{K_2})$

$E_1= 50,000-8.314*310.15*In(\frac{3.50*10^3}{1})$

$E_1 = 28957.39292$ $J/mol$

E₁ ≅ 28.96 kJ/mol

∴ the activation energy for a catalyzed biochemical reaction (E₁) = 28.96 kJ/mol

8 0

3 years ago

Classify the following reaction: When dissolved sodium chloride reacts with dissolved silver nitrate in water, aqueous sodium ni

Gnesinka [82]

Answer:

Explanation:

8 0

4 years ago

Write the empirical formula for at least four ionic compounds that could be formed from the following ions:

love history [14]

Answer:

$FeSO_{4},FeCH_{3}CO,Fe_{2}(SO_{4})_{3},Fe_{2}(CH_{3}CO)_{3}$

Explanation:

Empirical formula of ionic compound formed by two ions $A^{x+}$ and $B^{y-}$ is $A_{y}B_{x}$ (for $x\neq y$ ) of AB (for x = y)

The above empirical formula is in accordance with charge neutrality principle

Here each cation ( $Fe^{3+}$ and $Fe^{2+}$ ) can form two ionic compounds by combining with two given anions ( $SO_{4}^{2-}$ and $CH_{3}CO^{2-}$ ).

So the four ionic compounds are: $FeSO_{4},FeCH_{3}CO,Fe_{2}(SO_{4})_{3},Fe_{2}(CH_{3}CO)_{3}$

4 0

4 years ago