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klio [65]
3 years ago
8

Erica runs 5.3 kilometers every morning. One day, she runs 0.95 kilometers and then stops to take a break. How much further does

Erica have left to run?
Mathematics
1 answer:
Leviafan [203]3 years ago
8 0

Answer:

1foot(ft.)1yard(yd.)1mile(mi.)===12inches(in.)3feet(ft.)5,280feet(ft.)

Step-by-step explanation:

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Solve this : <br> 1. <img src="https://tex.z-dn.net/?f=6" id="TexFormula1" title="6" alt="6" align="absmiddle" class="latex-form
leonid [27]

6/2 (2+1)

6/ 2 x (3)

6/6 = 1

5 0
3 years ago
There is a group of 10 people ordering pizza. If each person
VashaNatasha [74]

Answer:

4

Step-by-step explanation:

If ten people each get three slices, they will need 30 pieces.

10 x 3 = 30

Each pizza has 8 slices, so we divide 30 by 8 to get the number of pizzas needed.

30 / 8 = 3.75

You can't buy 3.75 pizzas, so you must get 4 to ensure everyone gets enough.

4 0
3 years ago
Read 2 more answers
Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data
tresset_1 [31]

Based on the information represented by the boxplot ;

  • Latasha's lowest sale amount = 50

  • Kayla's median is between 200 and 300

  • Latasha has a greater spread due to higher IQR value

1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>

  • The minimum value is denoted by the starting position of the lower whisker on a boxplot.

  • Lowest amount of sale made by Latasha = 50

2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>

  • 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

  • 50% of sales made by Kayla is between 200 and 300

  • With median sale value being 250

3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>

  • The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

  • IQR = Upper Quartile (Q3) - Lower quartile(Q1)

<u>For Latasha</u> :

  • Q3 = 450 (Endpoint of the box)
  • Q1 = 150 (starting point of the box)

  • IQR = 450 - 150 = 300

<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>

  • Q3 = 375 (Endpoint of the box)
  • Q1 = 100 (starting point of the box)
  • IQR = 375 - 100 = 275

  • Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

4 0
2 years ago
The distance from first base to third base is 1.4times the distance from home plate to third base, which is k feet. REPRESENT TH
geniusboy [140]

Answer:

1.4 times k

Step-by-step explanation:

If k feet is the distance from home plate to third base, and the distance from first base to third base is 1.4 times the previous value, then

distance from first base to third base = 1.4 * k or 1.4 times k

If, for example, k=90 feet, then from first to third base there are

1.4*90=126 feet

4 0
3 years ago
Q: A is 8km due north of phone mast B. C is 9.5km due west of phone mast B. Calculate the distance AC
Evgen [1.6K]

Answer:

AC = 12.4 km (nearest tenth)

Step-by-step explanation:

AC can be calculated by using Pythagorean Theorem.

Thus:

AC² = AB² + BC²

Plug in the values

AC² = 8² + 9.5²

AC + √{154.25)

AC = 12.4 km (nearest tenth)

7 0
2 years ago
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