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nordsb [41]
4 years ago
7

The weight of an object is the product of its mass, m, and the acceleration of gravity, g (where g=9.8 m/s2). If an object’s mas

s is m=10. kg, what is its weight?
Physics
1 answer:
lina2011 [118]4 years ago
6 0

You just told us that  Weight = (mass) x (gravity),
and that mass=10kg and  gravity = 9.8 m/s².

All we need to do is write those numbers in place of the letters.

                     Weight = (10 kg) x (9.8 m/s²)  =  <em>98 newtons</em>.

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Explain why meteorologists compare new weather maps and weather maps that are 24 hours old​
lawyer [7]

To see which way atmospheric conditions and meteorological phenomena are moving, and how fast.

Also to see whether they were correct yesterday.

3 0
4 years ago
A watermelon is blown into three pieces by a large firecracker. Two pieces of equal mass m fly away perpendicular to one another
Alenkinab [10]

Answer:

Speed of larger piece is \dfrac{V\sqrt{2}}{3}

Explanation:

We apply the principle of conservation of momentum.

The watermelon is initially at rest. The initial momentum = 0 kg m/s in all directions.

After the collision,

Vertical momentum = momentum of piece in y-direction + y-component of momentum of larger piece = mV + 3mv_{ly}

Here, v_{ly} is the y-component of velocity of larger piece.

This is equal to 0, since the initial momentum is 0.

v_{ly}=\dfrac{V}{3}

Horizontal momentum = momentum of piece in x-direction + x-component of momentum of larger piece = mV + 3mv_{lx}

Here, v_{lx} is the x-component of velocity of larger piece.

This is also equal to 0, since the initial momentum is 0.

v_{lx}=\dfrac{V}{3}

The velocity of the larger piece, v_l, is the resultant of v_{lx} and v_{ly}. Since they are mutually perpendicular,

v_l = \sqrt{v_{ly}^2+v_{lx}^2}= \sqrt{\left(\dfrac{V}{3}\right)^2+\left(\dfrac{V}{3}\right)^2}

v_l = \dfrac{V\sqrt{2}}{3}

3 0
4 years ago
Which of the following is true about centripetal force? Check all that apply.
Artemon [7]

<u>The following statements are true about centripetal force :</u>

  • Without centripetal force, an object would continue in a straight
  • line.
  • Gravity can be a centripetal force, such as when it pulls a thrown
  • baseball down to the ground.
  • Friction can be a centripetal force, such as when it keeps a car on  the road going around a curve.

Answer: Option A, C, and D

<u>Explanation: </u>

Centripetal Force & Examples-

Centripetal force can be defined as the component of force that acts on an object in a curvilinear motion, directed towards the centre of axis of the circular path. This is the force responsible to pull an object in an inward direction and balance the pace on the path.

In the absence of the centripetal force, an object will either move in the direction of motion or on a straight path instead of moving inwards. It's also called as an "inward Force" as it tends to move the object towards the centre of the curved path.

As an example, a car moving on a circular road accelerates due to its constant change in direction since it's moving on a circular path. Now, the frictional force comes into picture that contributes its component as a centripetal force, pulling it towards the centre of the axis of the circular path.

Hence we can say that when a car turns on a circular path, friction force acts a centripetal force to maintain its motion and direction on the path. Talking about a baseball which is attracted by the gravitational force of the Earth and hence falls on the ground is clearly not the case of centripetal force as the path may not be circular every time and there is not axis of rotation.

Besides centripetal force, there is another force that acts on an object moving on a circular path but not in the inward direction. It is instead, equal and opposite of the centripetal force that draws the object away from the circular path of motion. Hence, it's called the "Outward force".

4 0
3 years ago
Read 2 more answers
Railroad car A rolls at a certain speed and makes a perfectly elastic collision with car B of the same mass. After the collision
lozanna [386]

Answer:

The speed of the car B after the collision is same as the speed of the car A before collision.

Explanation:

lets take the mass of the car A = m kg

Initial speed of the car A = u m/s

The mass of the car B = m  kg

Initial speed of the car A = 0 m/s

The final speed of the car A = 0 m/s

The final speed of the car B = v

There is no any external force on the masses that is why the linear momentum will be conserve.  

Initial linear momentum = Final linear momentum

P = mass  x velocity

m u + m x 0 = m x 0 +  m v

m u  + 0 = 0 + m v

m u = m v

v= u

Therefore we can say that ,the speed of the car B after the collision is same as the speed of the car A before collision.

4 0
4 years ago
A negative point charge q1 = 25 nC is located on the y axis at y = 0 and a positive point charge q2 = 10 nC is located at y =14
sergey [27]

Answer:

 y = 0.1 m

Explanation:

The electrical power for point loads is

         V = k \sum \frac{q_i}{r_i}k Sum qi / ri

in this case

         V = k (- \frac{q_1}{r_1 } + \frac{q_2}{r_2})

indicate that V = 0

        \frac{q_1}{r_1} = \frac{q_2}{r_2}

        r₂ = \frac{q_2}{q_1} r_1

the distance r1 is

         r₁ = y -0

the distance r2

         r₂ = 0.14 -y

we substitute

       

        0.14 - y = \frac{10}{25}  y

          y ( \frac{10}{25} + 1) = 0.14

          y 1.4 = 0.14

          y = 0.14 / 1.4

          y = 0.1 m

7 0
3 years ago
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