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lana66690 [7]
3 years ago
8

A negative point charge q1 = 25 nC is located on the y axis at y = 0 and a positive point charge q2 = 10 nC is located at y =14

cm. Find the y coordinate of the points where the net electric potential due to these two charges is zero.
Physics
1 answer:
sergey [27]3 years ago
7 0

Answer:

 y = 0.1 m

Explanation:

The electrical power for point loads is

         V = k \sum \frac{q_i}{r_i}k Sum qi / ri

in this case

         V = k (- \frac{q_1}{r_1 } + \frac{q_2}{r_2})

indicate that V = 0

        \frac{q_1}{r_1} = \frac{q_2}{r_2}

        r₂ = \frac{q_2}{q_1} r_1

the distance r1 is

         r₁ = y -0

the distance r2

         r₂ = 0.14 -y

we substitute

       

        0.14 - y = \frac{10}{25}  y

          y ( \frac{10}{25} + 1) = 0.14

          y 1.4 = 0.14

          y = 0.14 / 1.4

          y = 0.1 m

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Naddik [55]

Answer:

In order of increasing wavelength, the answer is:

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(ii) Radiation from an FM radio station at 93.1 MHz on the dial

(iii) A radio signal from an AM radio station at 680kHz on the dial

Explanation:

First, you have to know that the wavelength of a sinusoidal wave traveling at a constant speed is given by:  

                                       λ = \frac{v}{f}

Where λ is the wavelength, v is the constant speed and f is the wave's frequency. In the case of electromagnetic radiation in free space, the constant speed is the speed of light.

From explained above, you can conclude that there is a proportionality relationship between the wavelength and the frequency, they are inversely proportional. That means: the highest frequency will have the shortest wavelength and vice-versa.

So, you have the following types:

(i) The gamma rays produced by a radioactive nuclide used in medical imaging

Frequency : Typically greater than 10^{19} Hz

(ii) Radiation from an FM radio station at 93.1 MHz on the dial

Frequency: 93.1 MHz

(iii) A radio signal from an AM radio station at 680 kHz on the dial

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(iv) The yellow light from sodium-vapor streetlights

Frequency: Visible spectrum of approx. 508 - 526 THz

(v) The red light of a light-emitting diode, such as in a calculator display

Frequency: Visible spectrum of approx. 400 - 484 THz

Then, you have to organize them from the highest frequency to the smallest one (decreasing frequency), and as the highest frequency will have the shortest wavelength, you are going to have it organized in an increasing wavelength mode.

Then in order of increasing wavelength, the answer will be:

                                           (i) , (iv), (v), (ii), (iii)

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Anuta_ua [19.1K]

Answer:im just guessing d but i think its d though

Explanation:

it pretty obvious

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