Answer:
d = 0.247 mm
Explanation:
given,
λ = 633 nm
distance from the hole to the screen = L = 4 m
width of the central maximum = 2.5 cm
2 y = 0.025 m
y = 0.0125 m
For circular aperture
using small angle approximation
![\theta = \dfrac{y}{D}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Cdfrac%7By%7D%7BD%7D)
now,
d =0.247 x 10⁻³ m
d = 0.247 mm
the diameter of the hole is equal to 0.247 mm
Answer:
Wave A
<em>I</em><em> </em><em>hope this</em><em> </em><em>helps</em><em> </em>
W = F * s
Here, F = 50 N
s = 15 m
Substitute their values,
W = 50 * 15
W = 750 J
In short, Your Answer would be 750 Joules
Hope this helps!
Answer:
ramp b requires less force than ramp a
Explanation: