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This is how you calculate his speed, for the 100metres. That is, the average speed for the entire distance, including the start from intertia until the race end where the athlete is decelerating. Multiply the time by 10, and divide 3600 by that figure. i.e. 10 by10 equals 100. Divide 3600 by 100 and you get 36 which is the speed figure you requested.
A female athlete ran 200 metres a few years ago and in the middle section of the race covered 100 metres in that race in a time under 10 seconds. That is, she ran a sub 10second 100metres from a flying start. This great athlete from Slovenia, also ran a 100 metre race (from a stationary start) in a time under 11 seconds, when she was 48 years of age. Her name is Merlene Ottey.
Answer:

Explanation:
Work is energy transferred when an object is moved. It is the product of force and distance.

John did 3.2 Joules of work or 3.2 Newton meters of work (the units are equivalent). The window shade was lowered a distance of 0.8 meters.
Substitute the values into the formula.

We are solving for the force, so we must isolate the variable F. It is being multiplied by 0.8 meters. The inverse operation of multiplication is division, so divide both sides of the equation by 0.8 m.

The units of meters cancel.


John must exert <u>4 Newtons of force.</u>
<u>Answer </u>
34 N
<u>Explanation.</u>
I think the question is not complete.. It should be "<em>A box is pulled to the right with a force of 65 N at an angle of 58 degrees to the horizontal. The surface is frictionless. The free body diagram is shown. What is the net force in the x-direction? 30 N 34 N 55 N 65 N"</em>
We should find the horizontal component of the force 65 N.
Since 65 N is at an angle of 58° to the horizontal, we are required to find the horizontal force.
cosФ = adjacent/hypotenuse
let x be the net required (the component of 65N)
cos 58 = x/65
x = 65 × cos 58
= 34.44 N
frequency = speed of light / wavelength = 3 * 10^8/2.65 = 1.13 * 10^8
If the unit of wavelength is in meters, then 1.13 * 10^8 hertz is your answer. If it is in any other unit, you can derive for that one!!!