1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MatroZZZ [7]
3 years ago
7

What is the limiting reagent when 49.84 g of nitrogen react with 10.7 g of hydrogen according to this balanced equation: n2(g) 3

h2(g) → 2nh3(g) ?
Chemistry
2 answers:
Gennadij [26K]3 years ago
8 0
Moles of nitrogen = 49.84 / 28 = 1.78
Moles of hydrogen = 10.7 / 2 = 5.35

Molar ratio of nitrogen to hydrogen = 1 : 3
Hydrogen required = 1.78 x 3 = 5.34

Therefore, hydrogen is in excess and nitrogen is the limiting reagent. 

Firlakuza [10]3 years ago
8 0

<u>Answer:</u> The limiting reagent for the given chemical reaction is hydrogen.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}   .....(1)

  • <u>For Nitrogen:</u>

Given mass of nitrogen = 49.84 g

Molar mass of nitrogen = 28 g/mol

Putting values in above equation, we get:

\text{Moles of nitrogen}=\frac{49.84g}{28.0134g/mol}=1.78mol

  • <u>For Hydrogen:</u>

Given mass of hydrogen = 10.7 g

Molar mass of hydrogen = 2 g/mol

Putting values in above equation, we get:

\text{Moles of hydrogen}=\frac{10.7g}{2.01g/mol}=5.32mol

For the given chemical reaction:

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

By Stoichiometry of the reaction:

3 moles of hydrogen reacts with 1 mole of nitrogen.

So, 5.32 moles of hydrogen reacts with = \frac{1}{3}\times 5.32=1.77moles of nitrogen.

As, the given amount of nitrogen is more than the required amount, so it is considered as an excess reagent.

Thus, hydrogen is considered as an limiting reagent because it limits the formation of products.

Hence, the limiting reagent for the given chemical reaction is hydrogen.

You might be interested in
Calculate the standard emf for the following reaction:
krek1111 [17]
In order to solve this, we need to know the standard cell potentials of the half reaction from the given overall reaction.
The half reactions with their standard cell potentials are:
<span>2ClO−3(aq) + 12H+(aq) + 10e- = Cl2(g) + 6H2O(l) 
</span><span>E = +1.47 
</span>
<span>Br(l) + 2e- = 2Br- 
</span><span>E = +1.065
</span>
We solve for the standard emf by subtracting the standard emf of the oxidation from the reducation, so:
1.47 - 1.065 = 0.405 V
4 0
3 years ago
What are the five properties of hydrogen?
ratelena [41]
It is nontoxic, nonmetallic, odorless, tasteless, colorless
4 0
3 years ago
Which of the following is not equal to 0.536 kilometers? 53.6 hectometers (hm) 536 meters (m) 536,000 millimeters (mm) 53,600 ce
garri49 [273]
I believe it would be 53.6 hectometers, but I'm not 100% sure 
8 0
3 years ago
Read 2 more answers
Determine the volume, in liters, occupied by 0.050 moles of water vapor at STP.
hoa [83]

Answer:

delete this answer please

4 0
3 years ago
What is the empirical formula of a compound with a percent composition of 22.5% Phosphorous and 77.5% Chlorine?
sashaice [31]

Answer:

\boxed {\boxed {\sf PCl_3}}

Explanation:

We are given the percent composition: 22.5% phosphorus and 77.5% chlorine.

We can assume there are 100 grams of this compound. We choose 100 because we can simply use the percentages as the masses.

  • 22.5 g P
  • 77.5 g Cl

Next, convert these masses to moles, using the molar masses found on the Periodic Table.

  • P: 30.974 g/mol
  • Cl: 35.45 g/mol

Use the molar masses as ratios and multiply by the number of grams. 22.5 \ g \ P  * \frac {1 \ mol \ P }{30.974 \ g \ P}= \frac {22.5 \ mol \ P }{ 30.974} = 0.7264157035 \ mol \ P

77.5 \ g \ Cl  * \frac {1 \ mol \ Cl }{35.45 \ g \ Cl}= \frac {77.5 \ mol \ Cl }{ 35.45} \ =2.186177715 \ mol \ Cl

Divide both of the moles by the smallest number of moles to find the mole ratio.

\frac {0.7264157035} {0.7264157035} = 1

\frac {2.186177715}{0.7264157035}=3.009540824 \approx 3

The mole ratio is about 1 P: 3 Cl, so the empirical formula is written as:<u> PCl₃</u>

4 0
2 years ago
Other questions:
  • Round 23.455 cm into 4 significant figures
    10·2 answers
  • What is a dependent variable?
    14·2 answers
  • Apply Concepts H2O and H2O2 are binary molecular compounds generally known by their common names, “water” and “hydrogen peroxide
    14·1 answer
  • 1. Which of the following best describes natural selection?
    7·1 answer
  • Where is the sun located?
    9·1 answer
  • StitchXpika plzzzzzzzzz
    15·1 answer
  • 2C8H18 (1) + 2502 (g) --&gt; 16CO2 (g) + 18H2O (g)
    7·1 answer
  • At standard temperature and pressure. 0.500 mole of xenon gas occupies
    15·1 answer
  • Is decay pool or flux
    6·1 answer
  • A 2.0 L container of nitrogen gas had a pressure of 3.2 atm. What volume would be necessary to decrease the pressure to 1.0 atm
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!