Carbon + oxygen → carbon dioxide
Hope this helps!
Answer:
1-(tert-butoxy)-2-methylpropane
Note: there is a mistake in formula, the correct formula is (CH₃)₂-CH-CH₂-O-C(CH₃)₃ not (CH₃)₂-CH-CH₂-O(CH₃)₃, because oxygen is a divalent compound.
Explanation:
<em>Structural formula is attached</em>
IUPAC naming rules
1. start numbering the chain from the functional group. In this compound we start from oxygen side.
2. Here we can see that at position 1 there is an oxy group along with a tertiary carbon having three methyl groups. So we write it as 1-tert-butoxy. Which means that there is a methoxy group at position 1 along with a tertiary carbon.
3. At position 2 we can see that there is a methyl group attached to the main chain, so we write it as 2-methyl.
4. Now we count the total number of carbons in the main chain. As we can see that there are 3 carbons in the remaining or parent chain, so we write it as propane
5. So the IUPAC name of the compound will be 1-(tert-butoxy)-2-methylpropane
Answer:
Reaction is already balanced
Explanation:
The equation in reaction 1 is given as;
CH3COOH + NaHCO3 --> CO2 + H2O + Na+ + CH3COO-
The reaction is already balanced. This is because the umber of atoms of elements in the reactant is equal to that of the products
Carbon
Reactant = 2 + 1 = 3
Product = 2 + 2 = 3
Hydrogen
Reactant = 3 + 1 + 1 = 5
Product = 2 + 3 = 5
Oxygen
Reactant = 2 + 3 = 5
Product = 2 +1 + 2 = 5
Sodium
Reactant = 1
Product = 1
Hello!
the reaction:
sodium hydroxide + hydrochloric acid = sodium chloride
NaOH + HCl -> NaCl + H2O
if this helps, click “thanks” :)
- emily
<u>Answer:</u> The amount of sample left after 20 years is 288.522 g and after 50 years is 144.26 g
<u>Explanation:</u>
We are given a function that calculates the amount of sample remaining after 't' years, which is:

Putting values in above equation:


Hence, the amount of sample left after 20 years is 288.522 g
Putting values in above equation:


Hence, the amount of sample left after 50 years is 144.26 g