Answer:What is the molarity of a solution made with 126.32 g of sodium hydroxide dissolved to make 874.2 mL of solution? answer. 3.612 M NaOH. 3.612 M NaOH.
Explanation:
0.030 mol Na2S2O3
From the balanced equation, the <em>molar ratio</em> of Na2S2O3:Cl2 is 1:4.
∴ Moles of Na2S2O3 = 0.12 mol Cl2 x (1 mol Na2S2O3/4 mol Cl2)
= 0.030 mol Na2S2O3
<u>Answer:</u> The normality of unknown acid solution is 0.232 N
<u>Explanation:</u>
To calculate the normality of the unknown acid solution, we use the equation:
where,
are the normality and volume of the unknown acid solution
are the normality and volume of NaOH solution
We are given:
Putting values in above equation, we get:
Hence, the normality of unknown acid solution is 0.232 N
When magma cools down it turns into rocks these rocks are known as extrusive igneous rock