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Lady_Fox [76]
2 years ago
5

COg + 2H2g - CH3OHg. Given: 35g COg and 5.00g 2H2. How many molecules are in CH3OH?

Chemistry
1 answer:
neonofarm [45]2 years ago
7 0

To obtain number of atoms, multiply number of moles by the number of molecules per mole (Avogadro's number) and by the number of atoms per <u>molecule </u>(<u>in this case, there are six if you count them in CH3OH</u>). Therefore, 1.44 x 10^25 atoms in 128 grams of CH3OH.


I hope this helps and please mark brainlyest i need 5 to level up

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How many moles of silver chloride, produced from 100 g of silver nitrate reacting with barium chloride BaCl2?
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Answer:

Equation of Reaction

2AgNO3 + BaCl2 === 2AgCl + Ba(NO3)2

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Moles of reacting AgNO3 = 100g/170gmol-¹

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From the equation of reaction...2moles of AgNO3 reacts to Produce 2Moles of Silver Chloride

So Their ratio is 2:2.

This means that 0.588Moles of AgCl Will be produced too.

ANSWER...0.588MOLES OF AgCl WILL BE PRODUCED.

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After substantial heating, 6.25 g of iron produced 18.00 g of a compound with chlorine. The empirical formula is:
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Answer:

Option A. FeCl3

Explanation:

The following data were obtained from the question:

Mass of iron (Fe) = 6.25g

Mass of the compound formed = 18g

From the question, we were told that the compound formed contains chlorine. Therefore the mass of chlorine is obtained as follow

Mass of chlorine (Cl) = Mass of compound formed – Mass of iron.

Mass of chlorine (Cl) = 18 – 6.25

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The compound therefore contains:

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Chlorine (Cl) = 11.75g

The empirical formula for the compound can be obtained by doing the following:

Step 1:

Divide by their molar mass

Fe = 6.25/56 = 0.112

Cl = 11.75/35.5 = 0.331

Step 2:

Divide by the smallest

Fe = 0.112/0.112 = 1

Cl = 0.331/0.112 = 3

The empirical formula for the compound is FeCl3

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