Question

THIS IS DUE TODAY!!!!!!!!!!!!!!!!!!!!!!!!!! PLEASE HELP ME ASAPPPPPPPP CHEMISTRY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Answer:

$\large \boxed{\text{0.1767 mol/L}}$

Explanation:

(a) Balanced equation

3NaOH + H₃PO₄ ⟶ Na₃PO₄ + 3H₂O  

(b) Moles of NaOH

$\text{Moles of NaOH} = \text{34.52 mL NaOH} \times \dfrac{\text{0.3840 mmol NaOH}}{\text{1 mL NaOH}} = \text{13.26 mmol NaOH}$

(c) Moles of H₃PO₄

The molar ratio is 1 mol H₃PO₄:3 mol NaOH.

$\text{Moles of H _{3} PO}_{4} = \text{13.26 mmol NaOH} \times\dfrac{\text{ 1 mmol H _{3} PO}_{4}}{\text{3 mmol NaOH}}\\\\= \text{4.419 mmol H _{3} PO}_{4}$

(d) Molar concentration of H₃PO₄

$c = \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\c = \dfrac{n}{V} = \dfrac{\text{4.419 mmol}}{\text{25.00 mL}} = \text{0.1767 mol \cdot L ^{-1} }\\\\\text{The molar concentration of the NaOH is \large \boxed{\textbf{0.1767 mol/L}} }$