To solve this problem it is necessary to apply the concepts related to the Stefan-Boltzman law that is responsible for calculating radioactive energy.

Mathematically this expression can be given as

$P = \sigma Ae\Delta T^4$

Where

A = Surface area of the Object

$\sigma =$ Stefan-Boltzmann constant

e = Emissivity

T = Temperature (Kelvin)

Our values are given as

$A = 1.36m^2$

$\Delta T^4 = T_2^4 -T_1^4 = 307^4-T_1^4$

$\sigma = 5.67*10^{-8} J/(s m^2 K^4)$

$P = 122J/s$

$e = 0.7$

Replacing at our equation and solving to find the temperature 1 we have,

$P = \sigma Ae\Delta T^4$

$P = \sigma Ae (T_2^4 -T_1^4)$

$122 = (5.67*10^{-8})(1.36)(0.7)(307^4-T_1^4)$

$T_1 = 285.272K = 12.122\°C$

Therefore the the temperature of the coldest room in which this person could stand and not experience a drop in body temperature is 12°C

8 0

3 years ago

A syringe containing 1.54 ml of oxygen gas is cooled from 92.8 ∘c to 0.4 ∘c. what is the final volume vf of oxygen gas? (assume

Andrews [41]

Givens
=====
Ti = 92.8 oC = 92.8 + 273 = 365.8
T2 = 0.4 oC = 0.4 + 273 = 273.4

Vi = 1.54 mL
Vf = ?????

Formula
======
Vi/Ti = Vf / Tf
1.54 / 365.8 = Vf / 273.4

Calculations
=========
1.54 * 273.4 / 355.8 = Vf
vf = 1.15 mL

Comment
=======
if your teacher is concerned about sig digs, the answer is 1 mL. I'm not sure how to show that it is 1 sig dig. You can ask about this.

5 0

2 years ago

Which example shows potential energy? A. a skydiver falling B. a car racing C. hitting a nail with a hammer D. a wound up watch

tankabanditka [31]

B.a car racing down a hill

6 0

3 years ago

Read 2 more answers

A machine is supplied energy at a rate of 4,000 W and does useful work at a rate of 3,760 W. What is the efficiency of the machi

Dmitry_Shevchenko [17]

= (3,760 joule/sec) / (4,000 joule/sec)

= 3,760 / 4,000 = 0.94 = 94%

8 0

3 years ago