The total momentum should come out to be <span>2.0 x 10^4 kilogram meters/second </span>
To solve this problem it is necessary to apply the concepts related to the Stefan-Boltzman law that is responsible for calculating radioactive energy.
Mathematically this expression can be given as

Where
A = Surface area of the Object
Stefan-Boltzmann constant
e = Emissivity
T = Temperature (Kelvin)
Our values are given as





Replacing at our equation and solving to find the temperature 1 we have,




Therefore the the temperature of the coldest room in which this person could stand and not experience a drop in body temperature is 12°C
Givens
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Ti = 92.8 oC = 92.8 + 273 = 365.8
T2 = 0.4 oC = 0.4 + 273 = 273.4
Vi = 1.54 mL
Vf = ?????
Formula
======
Vi/Ti = Vf / Tf
1.54 / 365.8 = Vf / 273.4
Calculations
=========
1.54 * 273.4 / 355.8 = Vf
vf = 1.15 mL
Comment
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if your teacher is concerned about sig digs, the answer is 1 mL. I'm not sure how to show that it is 1 sig dig. You can ask about this.
= (3,760 joule/sec) / (4,000 joule/sec)
= 3,760 / 4,000 = 0.94 = 94%