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Alika [10]
2 years ago
9

Choose the items that are examples of unalienable rights.

Physics
2 answers:
Eduardwww [97]2 years ago
5 0

Answer:

the answer is D

Explanation:

bc the goverment cannot stop any religion from its service

Nana76 [90]2 years ago
3 0

The examples of unalienable rights include:

  • To live wherever you want to.
  • The government requiring safety standards in cars.
  • Not having the government listen to your phone calls.

In the declaration of Independence, the unalienable rights include life, liberty, and the pursuit of happiness.

It should be noted that one can live wherever one wants to. Also, one has the right to religion and should not be disturbed from practicing their religion. The government doesn't have the right to listen to one's phone calls too.

In conclusion, the correct options are A, C, and E.

Read related link on:

brainly.com/question/19097433

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A concert loudspeaker suspended high off the ground emits 34 W of sound power. A small microphone with a 1.0 cm2 area is 44 m fr
rjkz [21]

Answer:

<u>Part A</u>

I = 1.4 mW/m²  

<u>Part B</u>

β = 91.46 dB

Explanation:

<u>Part A</u>

Sound intensity is the power per unit area of sound waves in a direction perpendicular to that area. Sound intensity is also called acoustic intensity.

For a spherical sound wave, the sound intensity is given by;

                                            I = \frac{P}{A}

                                            I = \frac{P}{4\pi r^{2}}

Where;

P is the source of power in watts (W)

I is the intensity of the sound in watt per square meter (W/m2)

r is the distance r away

Given:

P = 34 W,

A = 1.0 cm²

r = 44 m

The sound intensity at the position of the microphone is calculated to be;

                                     I = \frac{34}{4\pi (44)^{2}}

                                     I = \frac{34}{4\pi (44)^{2}}

                                     I = 0.0013975 W/m²

                                 ≈  I = 0.0014 W/m² = 1.4 × 10⁻³ W/m²

                                     I = 1.4 mW/m²

The sound intensity at the position of the microphone is 1.4 mW/m².

<u>Part B</u>

Sound intensity level or acoustic intensity level is the level of the intensity of a sound relative to a reference value.  It is a a logarithmic quantity. It is denoted by β and expressed in nepers, bels, or decibels.

Sound intensity level is calculated as;  

                                    β = 10log_{10}\frac{I}{I_{0}}  dB

Where,

β is the Sound intensity level in decibels (dB)

I is the sound intensity;

I₀ is the reference sound intensity;

By pluging-in, I₀ is 1.0 × 10⁻¹² W/m²

           ∴        β = 10log_{10}\frac{1.4 * 10^{-3} W/m^{2}}{1.0 * 10^{-12} W/m^{2}}

                      β = 10log_{10} (1.4 * 10^{9})

                      β = 91.46 dB

The sound intensity level at the position of the microphone is 91.46 dB.                

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Answer:

B

Explanation:

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2 years ago
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If the second harmonic of a certain string is 42 Hz, what is the fundamental frequency of the string?
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A high school physics student is sitting in a seat reading this question. The magnitude of the force with which the seat is push
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in terms of magnitude 
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