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3 years ago

14

A segment of DNA that codes for the ability to make one type of protein molecule is known as a(n)____________________. A) axon B

) codon C) gene D) intron

2 answers:

Butoxors [25]3 years ago

4 0

Answer:

c-gene. Hope it helped!

Explanation:

astraxan [27]3 years ago

3 0

The answer is C) Gene

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What is a simple pendulum?

soldier1979 [14.2K]

Answer:

A pendulum is weight suspended from a pivot so that it can swing freely

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4 years ago

Using what you know about newton's second law explain why a car with a lager mass use more fuel than a car with a smalle mass. a

NNADVOKAT [17]

The car with bigger Mass requires more fuel because More mass the heavier it gets. you can't grab the little car fuel tank and put it in the big car it will run out to fast.

overall answer : The bigger the mass = more weight which means it needs more fuel to run

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3 years ago

With time running out in a game, Rachel runs towards the basket at a speed of 2.5 meters per second and from half-court, launche

finlep [7]

Answer:

Rachel(2.5,0)

ball(6.5,4.7)

b.R=10.15m/s, 27.57deg

Explanation:

The reference angle of Rachel is 0 $0^{0} while the ball is at 36^{0}$

resolving rachel's speed to the horizontal, we have

Ux=2.5cos0

Ux=2.5m/s

resolving rachel's speed to the vertical we have,

Uy=2.5sin0

Uy=0

for the ball

resolving the speed to its horizontal component

Ux=8cos36

Ux=6.5m/s

Uy=8sin36

Uy=4.7m/s

Rachel(2.5,0)

ball(6.5,4.7)

To get the resultant of their speed

Add the horizontal speed of rachel to that of the ball to get the total horizontal speed

Add the vertical speed of rachel and the ball to get the total vertical speed component

TUx=2.5+6.5=9M/S

TUy=0+4.7=4.7m/s

R= $\sqrt{(TUx^2+TUy^2}$

R= $\sqrt{(9^2+4.7^2}$

R= $\sqrt{(103)}$

R=10.15m/s

the direction

tan $\alpha$ =TUy/TUx

tan $\alpha$ =4.7/9

$\alpha$ =tan^-1(0.522)

$\alpha$ =27.57deg

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3 years ago

In certain cases, using both the momentum principle and energy principle to analyze a system is useful, as they each can reveal

SpyIntel [72]

Answer:

A) F_g = 26284.48 N

B) v = 7404.18 m/s

C) E = 19.19 × 10^(10) J

Explanation:

We are given;

Mass of satellite; m = 3500 kg

Mass of the earth; M = 6 x 10²⁴ Kg

Earth circular orbit radius; R = 7.3 x 10⁶ m

A) Formula for the gravitational force is;

F_g = GmM/r²

Where G is gravitational constant = 6.67 × 10^(-11) N.m²/kg²

Plugging in the relevant values, we have;

F_g = (6.67 × 10^(-11) × 3500 × 6 x 10²⁴)/(7.3 x 10⁶)²

F_g = 26284.48 N

B) From the momentum principle, we have that the gravitational force is equal to the centripetal force.

Thus;

GmM/r² = mv²/r

Making v th subject, we have;

v = √(GM/r)

Plugging in the relevant values;

v = √(6.67 × 10^(-11) × 6 x 10²⁴)/(7.3 x 10⁶))

v = 7404.18 m/s

C) From the energy principle, the minimum amount of work is given by;

E = (GmM/r) - ½mv²

Plugging in the relevant values;

E = [(6.67 × 10^(-11) × 3500 × 6 × 10²⁴)/(7.3 x 10⁶)] - (½ × 3500 × 7404.18)

E = 19.19 × 10^(10) J

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3 years ago

In a model of the solar system that was about as large as a college campus how large would the Sun be?

nordsb [41]

Small car is the answer

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3 years ago