What information is required when calculating speed or acceleration?
1 answer:
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Answer:
True
Explanation:
Scientific laws are often written as expressions that contains variables and are laws that are binding themselves.
In science, laws are natural phenomenon that draws from careful observations that holds through following a series of detailed study. Within the range of assumed parameters, a law will always hold true.
Most laws in science are denoted using mathematical variables which helps to interpret them.
The variables shows the relationship between the different parts of the law.
For example, Newton's law of universal gravitation is expressed mathematically as shown below;
F =
where G, m and r are all variables.
G is the universal gravitation constant
m is mass
r is the distance between them.
F is the gravitational force.
Most scientific laws are often expressed in this format.
Answer:
a. Please find the attached velocity time graph of the car's motion created with Microsoft Excel
b. The total distance traveled by the car is 8,725 meters
c. The average speed of the car is 22.9605263 m/s
Explanation:
The given parameters of the motion are;
The initial speed of the car, v₁ = 15 m/s
The time during which the car runs at the initial speed, t₁ = 30 seconds
The new speed the car then accelerates at 'a₁' to, v₂ = 25 m/s
The duration it takes for the car to accelerate to the new speed = 20 seconds
The time during which the car runs at the initial speed = 300 seconds
The time it takes the car to be brought to rest with a deceleration, 'a₂' from the new speed (20 m/s) = 30 seconds
The final speed of the car at rest, v₃ = 0 m/s
The acceleration, a₁ = (v₂ - v₁)/t₁ = (25 - 15)/20 = 1/2 m/s²
The deceleration , a₂ = (v₃ - v₂)/t₁ = (0 - 25)/30 = -5/6 m/s²
a. Please find attached the drawing of the velocity time graph of the motion created with Microsoft Excel
b. The total distance traveled by the car, 'Δx', is given b the area under the velocity time graph as follows;
Area of trapezoid, A₁ = (320 + 300)/2 × 10 = 3,100
Area of rectangle, A₂ = 15 × 350 = 5,250
Area of triangle, A₃ = 1/2×30×25 = 375
The total area under the velocity time graph = A₁ + A₂ + A₃ = 3,100 + 5,250 + 375 = 8,725
The total area under the velocity time graph = The total distance traveled by the car, Δx = 8,725 meters
c. The average speed of the car is given as follows;
Where;
Δt = The total time during which the car travels
∴ The average speed of the car = 8,725 m/(380 s) = 22.9605263 m/s
