In which eukaryotic organelle are amino acids and fatty acids oxidized?
1 answer:
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Specif gravity = density of the material / density of water
density of the material = specific gravity * density of water
density of gold = 19.3 * 1 g/mL = 19.3 g/mL
density = mass / volume ==> Volume = mass / density
Volume = 0.4 kg * 1000 g/kg / 19.3 g/mL = 20.725 mL
Length of one side of the cube =![\sqrt[3]{20.725 {cm}^{3} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B20.725%20%7Bcm%7D%5E%7B3%7D%20%7D%20)
= 2.75 cm
Pass cm to inches
2.75 cm * 1 inch / 2.54 cm = 1.08 inch
density of the material = specific gravity * density of water
density of gold = 19.3 * 1 g/mL = 19.3 g/mL
density = mass / volume ==> Volume = mass / density
Volume = 0.4 kg * 1000 g/kg / 19.3 g/mL = 20.725 mL
Length of one side of the cube =
Pass cm to inches
2.75 cm * 1 inch / 2.54 cm = 1.08 inch
<u>Answer:</u> The correct answer is Option b.
<u>Explanation:</u>
To calculate the amount of heat absorbed or released, we use the following equation:
.....(1)
where, q = amount of heat absorbed or released.
m = mass of the substance
c = heat capacity of water = 4.186 J/g ° C
= Change in temperature
- <u>For Trial 1:</u>
We are given:
Putting values in equation 1, we get:
q = 5023.2 J
- <u>For trial 2:</u>
We are given:
Putting values in equation 1, we get:
q = 1674.4 J
Heat gained by Trial 1 than trial 2 =
Hence, the amount of heat gained in Trial 1 about 3347 J more than the heat released in Trial 2.
Thus, the correct answer is Option b.