Polar solvents
hope it helps
Answer:
42672 kJ
Explanation:
Chemical reaction:
C₂H₄ + H₂ → C₂H₆ + heat
Now we calculate the number of moles of ethane C₂H₆:
number of moles = mass / molecular weight
number of moles of ethane = 10.1 / 30 = 0.336 kmoles = 336 moles
And determine the heat released:
if 127 kJ are released when 1 mole of C₂H₆ is produced
then X kJ are released when 336 moles of C₂H₆ is produced
X = (127 × 336) / 1 = 42672 kJ
Answer: this is because nutrients are increased by the movement of water.
Hope this helps! ^^
The volume of Sulfur dioxide-SO₂ at STP : = 102.144 L
<h3>Further explanation</h3>
Given
4.56 mol Sulfur dioxide-SO₂
Required
The volume
Solution
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.
so for 4.56 mol :
= 4.56 x 22.4 L
= 102.144 L
The answer for the following question is mentioned below.
<u><em>Therefore no of moles present in the gas are 1.12 moles</em></u>
Explanation:
Given:
Pressure of gas (P) = 1.2 atm
Volume of a gas (V) = 50.0 liters
Temperature (T) =650 K
To calculate:
no of moles present in the gas (n)
We know;
According to the ideal gas equation;
We know;
<u>P × V = n × R × T
</u>
where,
P represents pressure of the gas
V represents volume of the gas
n represents no of the moles of a gas
R represents the universal gas constant
where the value of R is 0.0821 L atm mole^{-1} K^-1
T represents the temperature of the gas
As we have to calculate the no of moles of the gas;
n = 
n = \frac{1.2*50.0}{0.0821*650}
n = \frac{60}{53.365}
n = 1.12 moles
<u><em>Therefore no of moles present in the gas are 1.12 moles</em></u>