Answer:
F = 520 N
Explanation:
For this exercise the rotational equilibrium equation should be used
Σ τ = 0
Let's set a reference system with the origin at the back of the refrigerator and the counterclockwise rotation as positive. On the x-axis it is horizontal directed outward, eg the horizontal y-axis directed to the side and the z-axis vertical
Torque is
τ = F x r
the bold indicate vectors, we analyze each force
the applied force is horizontal along the -x axis, the arm (perpendicular distance) is directed in the z axis,
The weight of the body is the vertical direction of the z-axis, so the arm is on the x-axis
-F z + W x = 0
F z = W x
F =
W
The exercise indicates the point of application of the force z = 1.5 m and the weight is placed in the center of mass of the body x = 0.6 m, we are assuming that the force is applied in the wide center of the refrigerator
let's calculate
F = 1300 0.6 / 1.5
F = 520 N
It would be B, the weather patterns outside.
Answer:
99 peanut butter
Explanation:
you minus 200 - 101 you get 99 peanut butter
Answer:
The magnitude of applied force,parallel to the incline is 575.38 N and parallel to the floor is 605 N.
Explanation:
Given:
Mass of the piano
= 190 kg
Inclined angle
= 18 degree
Considering gravity,
= 9.8
And
Using,
and 
<em>FBD diagram is attached with all the force acting on the floor and and the inclined. </em>
We have to find the magnitude of forces,when the man pushes it parallel to the incline and to the floor.
a.
When the man pushes it parallel to the incline.
Balancing the forces as
.
⇒ 
⇒ 
⇒ Here it is negative as the force is acting downward.
⇒ Plugging the values of mass
and angle
.
⇒ 
⇒
N
b.
When the force is parallel to the floor.
⇒ 
⇒ 
⇒ Plugging the values.
⇒ 
⇒
N
So,
The magnitude of applied force in inclined direction is 575.38 Newton and parallel to the floor is 605 N.