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What is the question yes it is converted to and then released
Answer:

Explanation:
<u>Densidad</u>
La densidad de una masa m que ocupa un volumen v se define como:

Tenemos que una masa de 80 gr hace que un volumen de agua se desplace desde 60 cm3 hasta 75 cm3, es decir, el volumen propio de la masa es m = 75 - 60 = 15 cm3.
Con esta información se calcula la densidad:

Operando:

Answer:
5.2 m
Explanation:
from the question we are given the following
depth of pool (d) = 3.2 m
height of laser above the pool (h) = 1 m
point of entry of laser beam from edge of water (l) = 2.5 m
we first have to calculate the angle at which the laser beam enters the water (∝),
tan ∝ = \frac{1}{2.2}
∝ = 24.44 degrees
from the attached diagram, the angle with the normal (i) = 90 - 24.4 = 65.56 degrees
lets assume it is a red laser which has a refractive index of 1.331 in water, and with this we can find the angle of refraction (r) using the formula below
refractive index = \frac{sin i}{sin r}
1.331 = \frac{sin 65.56}{sin r}
r = 43.16 degrees
we can get the distance (x) from tan r = \frac{x}{3.2}
tan 43.16 = \frac{x}{3.2}
x = 3 m
To get the total distance we need to add the value of x to 2.2 m
total distance = 3 + 2.2 = 5.2 m
Answer:
(a) Magnetic field at the center of the loop is 4.08 x 10⁻⁵ T
(b) Magnetic field at the axis of the loop is 5.09 x 10⁻⁹ T
Explanation:
Given :
Diameter of the circular loop = 2 cm
Radius of the circular loop, R = 1 cm = 0.01 m
Current flowing through the circular wire, I = 650 mA = 650 x 10⁻³ A
(a) Magnetic field at the center of circular loop is determine by the relation:

Here μ₀ is vacuum permeability constant and its value is 4π x 10⁻⁷ T m²/A.
Substitute the suitable values in the above equation.

B = 4.08 x 10⁻⁵ T
(b) Distance from the center of the loop, z = 20 cm = 0.2 m
Magnetic field at the point on the axis of the loop is determine by the relation:


B = 5.09 x 10⁻⁹ T