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3 years ago

Which element has atoms in the ground state with greatest number of valence electrons?

1 answer:

6 0

You need a list of elements to compare.

The procedure is to wirte the electron configuration and compare the number of electrons in the valence electron shell.

I will work with this list, to show you the procedure

(1) tin

(2) sulfur

(3) arsenic

(4) fluorine

element        atomic number   number of       abbreviated electron
                                                electrons        configuration

tin                  50                       50    [Kr] 5s^2 4d^10 5p2

sulfur             16                       16                  [Ne] 3s^2 3p^4

arsenic          33                       33                 [Ar] 4s^2 3d^10 4p^3

fluorine           9                          9                 [He] 2s^2 2p^5

The valence electrons are those in the last shell.

So, fluorine has 2 + 5 = 7 valence electrons, while tin has 2 + 2 = 4, sulfur has 2 + 4 = 6 and aersenic has 2 + 3 = 5.

Therefore, the answer is fluorine.

You might be interested in

aseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 5.5 g of methane is

maksim [4K]

Answer:

There is 9.6 grams of CO2 produced

Explanation:

Step 1: Data given

Mass of methane = 5.50 grams

Molar mass of methane = 16.04 g/mol

Mass of oxygen = 13.9 grams

Molar mass of oxygen = 32.0 g/mol

Step 2: The reaction

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Step 3: Calculate number of moles

Moles = mass / molar mass

Moles methane = 5.50 grams / 16.04 g/mol

Moles methane = 0.343 moles

Moles oxygen = 13.9 grams / 32.0 g/mol

Moles oxygen = 0.434 moles

For 1 mol CH4 we need 2 moles O2 to produce 1 mol CO2 and 2 moles H2O

O2 is the limiting reactant. It will completely react (0.434 moles).

There will react 0.434/2 = 0.217 moles CH4

There will remain 0.343-0.217 = 0.126 moles CH4

There will be produced 0.434 moles of H2O and

0.434/2 =0.217 moles of CO2

Step 4: Calculate mass of products

Mass = moles * molar mass

Mass CO2 = 0.217 moles ¨44.01 g/mol

Mass CO2 = 9.6 grams

Mass H2O = 0.434 moles * 18.02

Mass H2O = 7.8 grams

4 0

3 years ago

A sample of a compound made entirely from copper and oxygen was found to have a total mass of 0.143 g the mass of copper in the

tensa zangetsu [6.8K]

Mass of Oxygen: 0.0159 grams

Moles of Oxygen: 9.94x10^-4

To find the mass of oxygen, subtract the mass of copper from the total mass.

$0.143-0.1271=0.0159$

There are 0.0159 grams of Oxygen.

To find how many moles there are, divide the given amount of oxygen by the molar mass (atomic mass) of oxygen because that mass is the same as one mole of oxygen.

Molar mass of Oxygen: 16.00

$0.0159/16.00=9.94*10^{-4}$

There are 9.94*10^-4 moles of Oxygen.

6 0

1 year ago

Which has the reverse chemical reaction as

Mazyrski [523]

Answer:

please further explain your question

4 0

3 years ago

Which compounds represent the

Firlakuza [10]

Answer:

Both

compounds in left hand side of the equation is called reactants.

compounds in right hand side of the equation is called products.

so ans is both water and carbon di oxide

Explanation:

3 0

3 years ago

Calculate the mass of 0.25 mole of carbon dioxide

Fantom [35]

Answer:

11 g

Explanation:

1 mole of carbon dioxide =44 g

therefore for 0.25 mole = x

x = 44 × 0.25

x = 11.00g

7 0

3 years ago