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MissTica
3 years ago
14

What is the formula of Ammonium Sulphate?​

Chemistry
2 answers:
Kruka [31]3 years ago
5 0
_____________________________

Question: What is the formula of Ammonium Sulphate?

Answer: The formula of Ammonium Sulphate is (NH4)2SO4. It contains two atom of Nitrogen, eight atom of Hydrogen, four atom of Oxygen and one atom of sulphur. It is an acidic salt which is formed by the reaction of Ammonium Hydroxide and Sulphuric acid. It turns blue litmus paper into red which proves that it is acidic in nature.

_____________________________
DerKrebs [107]3 years ago
4 0

\bold{ANSWER}

AMMONUM SULPHATE =( NH4)2SO4

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Who hypothesized that electrons orbit around a nucleus? Bohr Greek philosophers Thomson Dalton
makvit [3.9K]

The answer to this question is bohr Greek


4 0
3 years ago
A sheet of gold weighing 8.8 g and at a temperature of 10.5°C is placed flat on a sheet of iron weighing 19.5 g and at a tempera
timofeeve [1]

Answer:

T = 36.393\,^{\textdegree}C

Explanation:

The contact between the sheet of gold and the sheet of iron allows a heat transfer until thermal equilibrium is done, which means that both sheets have the same temperature:

-Q_{iron} = Q_{gold}

-(0.008\,kg)\cdot (452\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (T-54.4\,^{\textdegree}C) = (0.0195\,kg)\cdot (129\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (T-10.5\,^{\textdegree}C)

-(3.616\,\frac{J}{^{\textdegree}C})\cdot (T-54.4\,^{\textdegree}C) = (2.515\,\frac{J}{^{\textdegree}C})\cdot (T-10.5^{\textdegree}C)

-1.438\cdot (T - 54.4^{\textdegree}C) = T-10.5^{\textdegree}C

-1.438\cdot T +78.227^{\textdegree}C = T - 10.5^{\textdegree}C

2.438\cdot T = 88.727\,^{\textdegree}C

The final temperature is:

T = 36.393\,^{\textdegree}C

8 0
3 years ago
Read 2 more answers
PLEASEEEE HELPPP I BEGGGG FOR HELPPP PLEASEE
belka [17]

Answer:

d

Explanation:

3 0
3 years ago
Read 2 more answers
An object has a mass of 4 grams and a volume of 2 cm^3.what is the density of the object?
stellarik [79]

Answer:

2.0 grams per cubic centimeter

Explanation:

(You can refer to the DMV triangle to help you solve this!)

Density = Mass/Volume

Density = 4.0g/2.0cm3

Density = 2.0g/cm3

Hope this helps!!!

-Unicorns110504

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3 0
3 years ago
Read 2 more answers
1) Given the balance equation below. Calculate how much Na3PO4 in grams you
juin [17]

Answer:

<u>136.67 g of Na3PO4 i</u>s required to create 100 gram of NaOH.

Explanation:

The balanced equation:

Na_{3}PO_{4} + 3 KOH \rightarrow 3 NaOH + K_{3}PO_{4}

1 mole Na3PO4 = 164 g/mole (Molar mass)

1 mole NaOH = 40 g/mole (Molar mass)

Now,

1 mole of Na3PO4 produce = 3 mole of NaOH

164 g/mol of Na3PO4 produce = 3(40) g/mol of NaOH

or

120 g/mol of NaOH is produced from = 164 g/mol of Na3PO4

1 g/mol of NaOH is produced from =

\frac{164}{120}

100 grams of NaOH is produced from =

\frac{164}{120}\times100 gram of Na3PO4

calculate,

= 136.67 g

8 0
3 years ago
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