Answer:
0.03g
Explanation:
Given parameters:
Number of moles of Na = 0.00125mole
Unknown:
Mass in grams of Na = ?
Solution:
To find the mass of this substance, we simply multiply the number of moles with the given molar mass of Na.
Mass of Na = number of moles x molar mass
Mass of Na = 0.00125 x 23 = 0.03g
Evaporation from the rivers, seas and so on,
and transpiration from the plants.
A non polar covalent bond because the electronegativity of the two atoms are not so different. Therefore the electron dwells equal for both atoms.
The question is incomplete, here is the complete question:
What volume (mL) of the partially neutralized stomach acid having concentration 2 M was neutralized by 0.1 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)
<u>Answer:</u> The volume of HCl neutralized is 1.25 mL
<u>Explanation:</u>
To calculate the volume of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of stomach acid which is HCl
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:

Hence, the volume of HCl neutralized is 1.25 mL
To satisfy the law of conservation of mass