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o-na [289]
3 years ago
9

Can you help me ASAPPP please help me

Physics
1 answer:
AveGali [126]3 years ago
6 0

Answer:it is a

Explanation hope this helps .

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A skydiver of 75 kg mass has a terminal velocity of 60 m/s. At what speed is the resistive force on the skydiver half that when
ankoles [38]

Answer:

The speed of the resistive force is 42.426 m/s

Explanation:

Given;

mass of skydiver, m = 75 kg

terminal velocity, V_T = 60 \ m/s

The resistive force on the skydiver is known as drag force.

Drag force is directly proportional to square of terminal velocity.

F_D = kV_T^2

Where;

k is a constant

k = \frac{F_D_1}{V_{T1}^2} = \frac{F_D_2}{V_{T2}^2}

When the new drag force is half of the original drag force;

F_D_2 = \frac{F_D_1}{2} \\\\\frac{F_D_1}{V_{T1}^2} = \frac{F_D_2}{V_{T2}^2} \\\\\frac{F_D_1}{V_{T1}^2} = \frac{F_D_1}{2V_{T2}^2} \\\\\frac{1}{V_{T1}^2} = \frac{1}{2V_{T2}^2}\\\\2V_{T2}^2 = V_{T1}^2\\\\V_{T2}^2= \frac{V_{T1}^2}{2} \\\\V_{T2}= \sqrt{\frac{V_{T1}^2}{2} } \\\\V_{T2}=  \frac{V_{T1}}{\sqrt{2} } \\\\V_{T2}=  0.7071(V_{T1})\\\\V_{T2}= 0.7071(60 \ m/s)\\\\V_{T2}= 42.426 \ m/s

Therefore, the speed of the resistive force is 42.426 m/s

8 0
3 years ago
Thirty-five percent of natural sunlight is made up of
Elden [556K]

Answer: Visible light makes up 35% of natural light.

5 0
3 years ago
Read 2 more answers
If you double the voltage in a circuit and reduce the resistance by a factor of four what will happen to the current? A) it will
KatRina [158]
By Ohm's Law, we can relate current, voltage and resistance. It is expressed as V=IR. That is, there is a direct relationship between voltage and resistance and voltage and current.

V = IR
V1/2V1 = I1R1 / I2R1/4
1/2 = 4I1/I2
I2 = 8I1

Therefore, <span> it will increase by a factor of 8. Hope this answers the question.</span>
5 0
3 years ago
Question 5 (1 point) What happens if there is NO oxygen present in cells?
Ivanshal [37]

Answer:

everything would die

Explanation:

8 0
3 years ago
Calculate the gravitational force between two elephants, one has a
Virty [35]

Answer:

2.177088 * 10^-8 N

Explanation:

solution;

mass(m1) = 1 * 10 kg

mass(m2) = 8 * 102 kg

distance(d) = 5m

universal gravitational constant (G) =6.67 * 10^-11

we know that,

gravitational force = (G*m1*m2)/d^2

=((6.67 *10^-11) *(1 *10)*(8 *102))/5^2

=(5.44272 * 10^-7)/25

=2.177088 *10^-8

Gravitational force = 2.177088 * 10^-8

8 0
2 years ago
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