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3 years ago

The Japanese 5 yen coin has a hole in the middle.

Mathematics

1 answer:

alexandr402 [8]3 years ago

5 0

Answer:

Subtract the two diameters and multiply by 0.5

Step-by-step explanation:

Calculating the Radius of the hole gives distance to the inner edges WHILE the Radius of the coin gives us the distance to the outer edges.

By subtracting the output we can then get the difference between both distances.

If hole diameter = 5mm and coin diameter = 22mm

Difference = [(22 - 5)mm] ÷ 2

17mm / 2 = 8.5mm

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Chain complete 40% of her homework on Monday and 2/3 on Tuesday if she started her homework on Monday what fractional part of he

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Answer:

1/5

Step-by-step explanation:

For Monday

The fraction of homework Chain completed =

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= 40% = 40/100

= 2/5

For Tuesday

The amount of home work left =

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3/5

The fraction of homework Chain completed on Tuesday = 2/3

= 2/3 Of 3/5

= 2/3 × 3/5

= 2/5

Let the total complete homework be represented by 1

Hence:

The Fractional part of her homework left for her to complete after Tuesday =

1 - (2/5 + 2/5)

Lowest common denominator is 5

= 1 - (2 + 2/5)

= 1 - (4 /5)

= 1/5

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