A.) top to bottom:
900, 1000, 1200
B.) top to bottom:
250, 450
The experimental evidence that you could provide that <span> the product isolated is 1-bromobutane would be the changes that happens that are observable by the naked eye. Hope this helps. Have a nice day. Feel free to ask more questions.</span>
Answer:
im pretty sure 2+
Explanation:
subtract the electrons from the protons
Answer:
32.1 g
Explanation:
Step 1: Write the balanced combustion reaction
C₄H₁₀ + 6.5 O₂ ⇒ 4 CO₂ + 5 H₂O
Step 2: Calculate the moles corresponding to 97.4 g of CO₂
The molar mass of CO₂ is 44.01 g/mol.
97.4 g × 1 mol/44.01 g = 2.21 mol
Step 3: Calculate the moles of butane that produced 2.21 moles of carbon dioxide
The molar ratio of C₄H₁₀ to CO₂ is 1:4. The moles of C₄H₁₀ required are 1/4 × 2.21 mol = 0.553 mol
Step 4: Calculate the mass corresponding to 0.553 moles of C₄H₁₀
The molar mass of C₄H₁₀ is 58.12 g/mol.
0.553 mol × 58.12 g/mol = 32.1 g
Answer:
7.22*10^24 molecules
Explanation:
Since one mole has 6.02*10^23 you'd multiply that number by 12
that equals 7.224*10^24 but you need sig figs
