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guajiro [1.7K]
4 years ago
14

Chemistry significant figures 3.42 + 8.132

Chemistry
1 answer:
olasank [31]4 years ago
7 0

3.42 + 8.132 = 11.55

Sig Figs

4

Decimals

2

Scientific Notation

1.155 × 101

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When (R)-6-bromo-2,6-dimethylnonane is dissolved in CH3OH, nucleophilic substitution yields an optically inactive solution. When
3241004551 [841]

Answer:

See explanation

Explanation:

The nucleophile here is CH3OH. We know that CH3OH is a good nucleophile that promotes SN2 reanction. However, (R)-6-bromo-2,6-dimethylnonane is a tertiary alkyl halide so the reaction proceeds by SN1 mechanism. This means that a racemic mixture is obtained at the end of the reaction because the attack occurs at the stereogenic carbon atom (6R) hence the product is optically inactive.

On the other hand, when (5R)-2-bromo-2,5-dimethylnonane is reacted with CH3OH, an optically active product is obtained because; though a tertiary alkyl halide and reaction occurs by SN1 mechanism, the attack does not occur at the stereogenic carbon atom (5R). Therefore, an optically active product is obtained in this case.

7 0
3 years ago
Is precipitate in water an electrolyte solution
vagabundo [1.1K]
When no ions are produced, or the ion content is low, the solute is a non-electrolyte. Non-electrolytes do not conduct electricity or conduct it to a very small degree. In an aqueous solution a strong electrolyte is considered to be completely ionized, or dissociated, in water, meaning it is soluble
4 0
3 years ago
3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases by 1
nordsb [41]

<u>Answer:</u> The enthalpy change of the unknown solid is 3.824 kJ/mol

<u>Explanation:</u>

To calculate the mass of solution , we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 1.20 g/mL

Volume of solution = 150.0 mL

Putting values in above equation, we get:

1.20g/mL=\frac{\text{Mass of solution}}{150.0mL}\\\\\text{Mass of solution}=(1.20g/mL\times 150.0mL)=180g

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T

q = heat absorbed or released

m = mass of solution = 180 g

c =  specific heat capacity = 4.18 J/g°C

\Delta T = change in temperature = 16.01°C

Putting values in above equation:

Q=180\times 4.18\times 16.01=12045.9J=12.046kJ

To calculate the enthalpy change of the reaction, we use the equation

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat absorbed = 12.046 kJ

n = number of moles of solid = 3.15 moles

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{12.046kJ}{3.15mol}=3.824kJ/mol

Hence, the enthalpy change of the unknown solid is 3.824 kJ/mol

5 0
3 years ago
Difference between saturated and supersaturated solutions
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Saturated had as much solute that it can hold, supersaturated holds more than can normally be dissolved.
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A compound isolated from a biological source is subjected to chemical analysis. It contains carbon and oxygen in roughly equal a
mafiozo [28]

the answer is glycogen

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