Answer:
8,809.024m
Explanation:
Displacement , y = (gt^2/2
)
g = 9.8 m/s^2
t = 42.4s
y = (9.8 (42.4*42.4)) / 2
y = 8,809.024m
Answer:
The angle of launch is 52.49 Degree.
Explanation:
The Range R and Height H of a thrown object is calculated using the formula,
R=V₀² sin(2φ)/g
H=V₀²sin²(φ)/g
From these equations it can be written,
V₀²=R g/ sin(2φ)
V₀²=H g/ sin²(φ)
These values are equal so it can be written by equating these equations,
R g/sin(2φ)=H g/sin²(φ)
tan(φ)= 2H/R
Given H=72.3 m and R=111 m, the angle of launch is,
tan(φ)= 2*72.3/111
φ= 52.49 Degree.
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Answer: The speed limit is 15 mph when you come within 100 feet of a railroad crossing and you cannot see the tracks for 400 feet in both directions. You may go faster than 15 mph if the crossing is controlled by gates, a warning signal, or a flagman.
Explanation: hope this helps
Answer:
C. Overcome Friction
Explanation:
When using any machine usually those with moving parts, you may notice heat forming near the areas where most movement occurs. As friction continues, more energy is used up and released as heat. For that reason, the efficiency of a machine will forever be less than 100%
