In collision that are categorized as elastic, the total kinetic energy of the system is preserved such that,
KE1 = KE2
The kinetic energy of the system before the collision is solved below.
KE1 = (0.5)(25)(20)² + (0.5)(10g)(15)²
KE1 = 6125 g cm²/s²
This value should also be equal to KE2, which can be calculated using the conditions after the collision.
KE2 = 6125 g cm²/s² = (0.5)(10)(22.1)² + (0.5)(25)(x²)
The value of x from the equation is 17.16 cm/s.
Hence, the answer is 17.16 cm/s.
I would go with C but that's just my personal opinion, I chose C because she only did it to group A
The force on the layer will be equivalent to the weight of water on it. This is given by:
F = mg; m is the mass of water and g is the acceleration due to gravity.
Answer:
Explanation:
The frequency of a simple pendulum is given by:
where
g is the acceleration of gravity
L is the length of the pendulum
Calling 
the length of the first pendulum and 
the acceleration of gravity at the location of the first pendulum, the frequency of the first pendulum is
The length of the second pendulum is 0.4 times the length of the first pendulum, so
while the acceleration of gravity experienced by the second pendulum is 0.9 times the acceleration of gravity experienced by the first pendulum, so
So the frequency of the second pendulum is
Therefore the ratio between the two frequencies is
Answer:
≅ 17000 years or 1.7 x 10⁴ years
Explanation:
time= total energy/power
= (10⁸J/kg)(2x10³⁰ kg) / 3.8 x 10²⁶ J/s
= 526,315,789,473 s
= 16689 years
≅ 17000 years or 1.7 x 10⁴ years
