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Romashka [77]
4 years ago
9

A wire is wrapped 200 times around a hollow cylinder of cross-sectional area 12 cm2 and length 10 cm. Assuming the turns are spr

ead out evenly over the length of the cylinder, how much energy is stored in this coil when the wire carries a current of 6 A
Physics
1 answer:
Sonja [21]4 years ago
7 0

Answer:

The answer is 10.857mJ

Explanation:

The energy stored in this solenoid is given by the below mentioned equation,

U = L*I^{2}/2

where L the inductance of this solenoid is given by the below mentioned equation,

L = u_{0} *N^{2}*A/L

Plugging this into the energy equation you obtain the equation for the total energy stored in the magnetic field of the solenoid, given by,

U = u_{0} *N^{2}*A*I^{2}/(2*L)

where u_{0} is the permeability of free space which equals to u_{0} = 4*\pi *10^{-7} T.m/A. Plugging all the quantities into the above equation from the data in the question after converting to standard units. of meters instead of centimeters, we get for the energy stored in the coil,

U = 10.857mJ

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The period will be the same if the amplitude of the motion is increased to 2a

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Amplitude refers to the maximum extent of a vibration or oscillation, measured from the position of equilibrium.

Here,

mass m is attached to the spring.

mass attached = m

time period = t

We know that,

The time period for the spring is calculated with the equation:

T = 2\pi \sqrt{\frac{m}{k} }

Where k is the spring constant

Now if the amplitude is doubled, it means that the distance from the equilibrium position to the displacement is doubled.

From the equation, we can say,

Time period of the spring is independent of the amplitude.

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Increasing the amplitude does not affect the period of the mass and spring system.

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This technique allowed multiple peoples DNA to be compared to look for
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A ski hill is angled 20° above the horizontal. If a skier starts from rest at the top of the hill, how fast will she be travelin
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Answer:

20 m/s

Explanation:

First, we calculate for the acceleration down the incline using a = gsin\theta.

a = (9.80)sin(20°)

a = 3.35

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v_{i} = 0 m/s

a = 3.35

\Delta s = 62 m

v_{f} = \sqrt{2(3.35)(62)}

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If several ball are thrown straight up with different initial speeds, the quantity that will hve the same value along their path
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<em><u>D. acceleration Hope this helps!</u></em>

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3 years ago
A 0.5kg stone moving north at 4 m/s collides with a 4kg lump of clay moving west at 1 m/s. The stone becomes embedded in the cla
sergij07 [2.7K]

Answer:

The velocity of the composite body is 0.99m/s 63.43° west of north.

Explanation:

Here the law of conservation of energy says that

(1).\: \: m_1v_1cos(0)+m_2v_2cos(90^o)=(m_1+m_2)v_f cos(\theta)

(2).\: \: m_1v_1sin(0)+m_2v_2sin(90^o)=(m_1+m_2)v_f sin(\theta)

where v_f is the final velocity if the composite body, and \theta is measured from west of north.

Putting in numbers and simplifying the above equation we get:

(3).\: \: m_1v_1=(m_1+m_2)v_f cos(\theta)

(4).\: \: m_2v_2=(m_1+m_2)v_f sin(\theta)

dividing equation (4) by (3) gives

\dfrac{ m_2v_2=(m_1+m_2)v_f sin(\theta)}{ m_1v_1=(m_1+m_2)v_f cos(\theta)}

\dfrac{m_2v_2}{m_1v_1} = \dfrac{sin(\theta)}{ cos(\theta)}

(5).\: \:  tan(\theta) = \dfrac{m_2v_2}{m_1v_1}

putting in m_1 = 0.5kg, v_1 = 4m/s, m_2 = 4kg, and v_2 = 1m/s we get:

tan(\theta) = \dfrac{(4kg)(1m/s)}{(0.5kg)(4m/s)}

\boxed{\theta = 63.43^o}

Thus, the final velocity v_f we get from equation (3) is:

v_f=\dfrac{m_1v_1}{(m_1+m_2)cos(\theta)}

v_f=\dfrac{(0.5kg)(4m/s)}{(4kg+0.5kg)cos(63.43^o)}

\boxed{v_f = 0.99m/s}

Thus, the velocity of the composite body is 0.99m/s 63.43° west of north.

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3 years ago
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