Explain good experimental procedure

In the space around a permanent magnet, where is the magnetic field the strongest?

BlackZzzverrR [31]

near the north and south poles of the magnet

Explanation:

Magnetic fields around a permanent magnet is strongest near the north and south poles of the magnet.

Magnetic fields are the region of space around a magnet where magnetic effects are felt.

This is as a result of a force field that surrounds the magnet.
Magnetic fields are strongest within the magnet.
Also, externally, they are strongest at the poles of a magnet.
Around the poles, magnetic lines of force leaves and enters a magnet.

learn more;

Electromagnet brainly.com/question/2191993

#learnwithBrainly

6 0

3 years ago

Which of the following ocean-floor features would contain the newest rocks?

Amiraneli [1.4K]

The further away from the mid-ocean ridge, the older the rocks are on the ocean floor. Therefore, the ocean floor feature that would contain the newest rocks would be the mid-ocean ridge.

7 0

3 years ago

Read 2 more answers

What is the average kinetic energy of helium atoms in a region of the solar corona where the temperature is 5.90 x 10^5 K?

OLEGan [10]

<u>Answer:</u> The average kinetic energy of helium atoms is $1.222\times 10^{-17}J$

<u>Explanation:</u>

To calculate the average kinetic energy of the atom, we use the equation:

$K=\frac{3}{2}kT$

where,

K = average kinetic energy = ?

k = Boltzmann constant = $1.3807\times 10^{-23}J/K$

T = temperature = $5.9\times 10^5K$

Putting values in above equation, we get:

$K=\frac{3}{2}\times 1.3807\times 10^{-23}J/K\times 5.9\times 10^5K\\\\K=1.222\times 10^{-17}J$

Hence, the average kinetic energy of helium atoms is $1.222\times 10^{-17}J$

4 0

3 years ago

A moving curling stone, A, collides head on with stationary stone, B. Stone B has a larger mass than stone A. If friction is neg

Kitty [74]

Answer:

The correct answer is option 'c': Smaller stone rebounds while as larger stone remains stationary.

Explanation:

Let the velocity and the mass of the smaller stone be 'm' and 'v' respectively

and the mass of big rock be 'M'

Initial momentum of the system equals

$p_i=mv+0=mv$

Now let after the collision the small stone move with a velocity v' and the big roch move with a velocity V'

Thus the final momentum of the system is

$p_f=mv'+MV'$

Equating initial and the final momenta we get

$mv=mv'+MV'\\\\m(v-v')=MV'.....i$

Now since the surface is frictionless thus the energy is also conserved thus

$E_i=\frac{1}{2}mv^2$

Similarly the final energy becomes

$E_f=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2$ \

Equating initial and final energies we get

$\frac{1}{2}mv^2=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\\\\mv^2=mv'^2+MV'^2\\\\m(v^2-v'^2)=MV'^2\\\\m(v-v')(v+v')=MV'^2......(ii)$

Solving i and ii we get

$v+v'=V'$

Using this in equation i we get

$v'=\frac{v(m-M)}{(M-m)}=-v$

Thus putting v = -v' in equation i we get V' = 0

This implies Smaller stone rebounds while as larger stone remains stationary.

4 0

3 years ago

An open pipe is 1.42 m long

lora16 [44]

Answer:

the fundamental frequency produced by the open pipe is 120.78 Hz

Explanation:

Given;

length of the open pipe, L = 1.42 m

speed of sound in air, v = 343 m/s

The length of the open pipe for the fundamental frequency is equivalent to half of wavelength;

$L = \frac{\lambda}{2} \\\\\lambda = 2L$

The fundamental frequency produced by the open pipe is calculated as;

$f_o = \frac{v}{\lambda} \\\\f_o = \frac{v}{2L} \\\\f_o = \frac{343}{2 \times 1.42} \\\\f_o = 120.78 \ Hz$

Therefore, the fundamental frequency produced by the open pipe is 120.78 Hz

6 0

3 years ago