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Anika [276]
3 years ago
5

It is determined that a certain light wave has a wavelength of 3.012 ×10−12 m. The light travels at 2.99 ×108 m/s. What is the f

requency of the light wave? (Round your answer to three significant figures.)
Physics
1 answer:
horsena [70]3 years ago
5 0

Answer:

Explanation:

velocity=frequency*wavelength

velocity = 2.99*10^8 m/s

frequency = ?

wavelength = 3.012*10^-12

2.99*10^8m/s = (f)(3.012*10^-12)

f=9.58*10^19 Hertz    

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C. Alpha

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Your grandmother enjoys creating pottery as a hobby. She uses a potter's wheel, which is a stone disk of radius R-0.520 m and ma
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0.54454

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m = Mass of wheel = 100 kg

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\omega_f = Final angular velocity

\omega_i = Initial angular velocity

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Mass of inertia is given by

I=\dfrac{mr^2}{2}\\\Rightarrow I=\dfrac{100\times 0.52^2}{2}\\\Rightarrow I=13.52\ kgm^2

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\alpha=\dfrac{\tau}{I}\\\Rightarrow \alpha=\dfrac{\mu fr}{I}\\\Rightarrow \alpha=\dfrac{\mu 50\times 0.52}{13.52}

Equation of rotational motion

\omega_f=\omega_i+\alpha t\\\Rightarrow \omega_f=\omega_i+\dfrac{\mu (-50)\times 0.52}{13.52}t\\\Rightarrow 0=60\times \dfrac{2\pi}{60}+\dfrac{\mu (-50)\times 0.52}{13.52}\times 6\\\Rightarrow 0=6.28318-11.53846\mu\\\Rightarrow \mu=\dfrac{6.28318}{11.53846}\\\Rightarrow \mu=0.54454

The coefficient of friction is 0.54454

At r = 0.25 m

\omega_f=\omega_i+\dfrac{0.54454 (-50)\times 0.52}{13.52}6\\\Rightarrow 0=60\times \dfrac{2\pi}{60}+\dfrac{0.54454 f\times 0.25}{13.52}6\\\Rightarrow 2\pi=0.06041f\\\Rightarrow f=\dfrac{2\pi}{0.06041}\\\Rightarrow f=104.00902\ N

The force needed to stop the wheel is 104.00902 N

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An object of unknown mass is initially at rest and dropped from a height h. It reaches the ground with a velocity v1 . The same
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Answer:

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It means that v₂ is √2 times v₁.

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