Answer:
a = 0.5195 m/s²
θ = 9.997º ≈ 10º
Explanation:
We apply Newton's 2nd Law as follows:
∑ Fx = m*ax
∑ Fy = m*ay
Then we have
∑ Fx = F₁x + F₂x = m*ax ⇒ 600*Cos 40º + 600*Cos (-20º) = 2000*ax
⇒ ax = 0.5117 m/s²
∑ Fy = F₁y + F₂y = m*ay ⇒ 600*Sin 40º + 600*Sin (-20º) = 2000*ay
⇒ ay = 0.0902 m/s²
the magnitude of the acceleration of the barge is
a = √(ax² + ay²) = √((0.5117 m/s²)² + (0.0902 m/s²))= 0.5196 m/s²
and the direction is
θ = Arctan (ay / ax) = Arctan (0.0902 / 0.5117) = 9.997º ≈ 10º
Answer:
The acceleration of the car is 5m/s²
Explanation:
Given data
Force F= 4,000N
Mass of car m= 800kg
Acceleration a= ?
Applying the Newton's second law of motion which states that the rate of change of momentum of a body is proportional to the external force and takes place in the direction of the force
F=ma
a= F/m
a= 4000/800
a=5m/s²
The answer is comparative.