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3 years ago

There is an upper limit on the speed of a particle. This means there is also an upper limit on its

Physics

1 answer:

Dafna11 [192]3 years ago

5 0

Answer:

As speed of a particle has a limit so does its momentum has a limit.

Explanation:

As we know that in this Universe no information can travel faster than the speed of light.

The speed of light is the fastest possible speed and hence the quantities dependent on it also have certain limits.

The momentum of a body at normal non-relativistic speed is given as:

$p=m.v$

The momentum of a body at relativistic speed (a speed of the order of speed of light) is given as:

$p=m.v.\gamma$

here

$\gamma =\frac{1}{\sqrt{1-\frac{v^2}{c^2} }}$ Lorentz factor

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Who’s has bigger cross sectional area capillaries or aorta?

Natalka [10]

Answer:

Even though the cross-sectional area of each capillary is extremely small compared to that of the large aorta, the total cross-sectional area of all the capillaries added together is about 1,300 times greater than the cross-sectional area of the aorta because there are so many capillaries

Explanation:

8 0

2 years ago

Emboldened by the success of their late night keg pull in Exercise 61 above, our intrepid young scholars have decided to pay hom

alexdok [17]

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2 years ago

In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy without the aid of a pole.

Fiesta28 [93]

Answer:

6.0 m/s

Explanation:

According to the law of conservation of energy, the total mechanical energy (potential, PE, + kinetic, KE) of the athlete must be conserved.

Therefore, we can write:

$KE_i+PE_i =KE_f+PE_f$

$\frac{1}{2}mu^2+0=\frac{1}{2}mv^2+mgh$

where:

m is the mass of the athlete

u is the initial speed of the athlete (at the bottom)

0 is the initial potential energy of the athlete (at the bottom)

v = 0.80 m/s is the final speed of the athlete (at the top)

$g=9.8 m/s^2$ is the acceleration due to gravity

h = 1.80 m is the final height of the athlete (at the top)

Solving the equation for u, we find the initial speed at which the athlete must jump:

$u=\sqrt{v^2+2gh}=\sqrt{0.80^2+2(9.8)(1.80)}=6.0 m/s$

4 0

3 years ago

A book starts on a shelf 1 m off of the ground. You then move the book to a higher shelf that is 3 m off of the ground. If the s

JulsSmile [24]

Answer:

Using g = 9.8: 1.02 kg, Using g = 10: 1 kg

Explanation:

E = mgh

20 = m(9.8)(3 - 1)

20 = 9.8m(2)

20 = 19.6m

m = 1.02 kg

I'm now assuming you may be using a g constant of 10, thus the close integer result, in which case the mass would be exactly 1 kilogram.

4 0

3 years ago

The atomic mass of nitrogen is 14.01, hydrogen is 1.01, sulfur is 32.07, and oxygen is 16.00. What is the molar mass of ammonium

MArishka [77]

The molar mass of ammonium sulphate [(NH4)2SO4] is 132.17 g (option E). Details about molar mass can be found below.

<h3>How to calculate molar mass?</h3>

The molar mass of a substance can be calculated by adding the atomic masses of the elements in the compound.

According to this question, the atomic mass of nitrogen is given as 14.01, hydrogen is 1.01, sulfur is 32.07, and oxygen is 16.00.

The molar mass of ammonium sulphate is as follows:

[(NH4)2SO4] = [14.01 + 1(4)]2 + 32.07 + 16.00(4)

= 36.02 + 32.07 + 64

= 132.09

Therefore, the molar mass of ammonium sulphate [(NH4)2SO4] is 132.17 g.

Learn more about molar mass at: brainly.com/question/12127540

#SPJ1

4 0

1 year ago